Conservation of Momentum law problem

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SUMMARY

The discussion centers on solving a conservation of momentum problem involving two masses, m1 (3kg) and m2 (6kg), with initial velocities v1 (5m/s) and v2 (2m/s). The conservation of momentum equation m1v1 + m2v2 = m1v1' + m2v2' is confirmed as correct, leading to the derived equation 27 = 3v1' + 6v2'. Additionally, the conservation of kinetic energy equation m1v1^2 + m2v2^2 = m1v1'^2 + m2v2'^2 yields 99 = 3v1'^2 + 6v2'^2. The discussion emphasizes the relationship between v1 and v2, suggesting that v1 can be expressed in terms of v2 for further calculations.

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  • Understanding of conservation of momentum principles
  • Familiarity with elastic collision equations
  • Basic algebra for solving equations
  • Knowledge of quadratic equations for solving motion problems
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  • Learn how to solve quadratic equations related to motion problems
  • Explore examples of two-body collision problems in physics
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Homework Statement


m1= 3kg m2= 6kg
v1 = 5m/s v2= 2m/s
d = 3m
DIAGRAM : http://gyazo.com/17b3126726b109256a35f65b86708bb0

Homework Equations


Conservation of momentum:
m1+v1 = m1v1'+m2v2'

Conservation of elastic:
m1v1^2+m2v2^2 = m1v1'^2+m2v2'^2

The Attempt at a Solution


Now my attempt was use both equations & the answers I've gotten so far are 27=3v1'+6v2'(for conservation of momentum) & the 2nd one I've got for the conservation of elastic is 99= 3v1'^2 + 6v2'^2 since they will collide at some point. The only thing I'm stuck at is what to do next afterwards. My teacher has done a similar question but I can never understand how he did it.
 
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Is the conservattion of momentum law correct ??!
I mean Is it llike what you wrote or like the following
m1v1 + 0 = m1v1+m2v2

Zero indecates that the momentum is zero because the vilocity of the second ball before collision is zero ..
Am I right ..
 
Sorry v1 has a value
so the will be
m1v1 +m2v2 = m1v1+m2v2
 
Im just stuck because the example that my teacher gave was like "50=2(10-3v2'/2)^2+3v2'^2" that bracket part confuses me
 
Try to equte the two equation or write v1 in term of v2..
 
Maged Saeed said:
Try to equte the two equation or write v1 in term of v2..
WOW WHAT THE ****, OK I DID THAT ONE BEFORE. Its this right? " V1+V1' = V2+V2'" but can u explain why that is that cus it made some sense to me. & I showed my friend this process but, she said it made no sense so.
 
I think your teacher has written v1 in term of v2
try to do so from the first equation your v1 will be (27 - 6 v2) /3 which is 9-2v2

It seems reasonable
;)
 
Maged Saeed said:
I think your teacher has written v1 in term of v2
try to do so from the first equation your v1 will be (27 - 6 v2) /3 which is 9-2v2

It seems reasonable
;)
but why is that though? :( pls
 
Because v1 and v2 are related by these two equations and their value must satisfy both of them
so we make this substitution
I hope that I understand your question and answer it ..
o_O
 
  • #10
Maged Saeed said:
Because v1 and v2 are related by these two equations and their value must satisfy both of them
so we make this substitution
I hope that I understand your question and answer it ..
o_O
alright thaanks dawg really appreciate that, last question in the example he gave so the last line was 50-50 = -30v2'+7.5v2'^2
the left side what if it wasnt 0
 
Last edited:
  • #11
If the lift side isn't zero move it to the right side and solve the quadratic equation..

By the way what does dawg mean in your last comment
o_O
 
  • #12
Maged Saeed said:
If the lift side isn't zero move it to the right side and solve the quadratic equation..

By the way what does dawg mean in your last comment
o_O
means like dude lol kids these days
 

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