- #1

- 6

- 0

a) If the railway gun was at rest before firing and moved to the right at a speed of 5.21 m/s immediately after firing, what was the speed of the projectile as it left the barrel (muzzle speed)? Assume that the wheel axles are frictionless.

b) How far will the projectile travel if air resistance is neglected?

m1*v1=m2*v2

I have attempted this with conservation of momentum.

(1.22*10^6kg)(5.21m/s)=7502(v2)

v2=847.27

I then realized i had to break it up into components. I know that the x component of the projectile would be 5.21 m/s so to find the y component I did this:

cos(24.7)=5.21/y

ycos(24.7)=5.21

y=5.73m/s

I then used vector addition,

v=√(5.73^2+5.21^2)

v=7.74 m/s

This answer was incorrect, I also tried entering it as a negative number which was wrong.

Any help would be appreciated!