Conservation of momentum problem in variable.

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SUMMARY

The discussion centers on a conservation of momentum problem involving Tarzan and Jane, where Tarzan of mass M swings from a height H and, upon reaching the bottom of the arc, collides inelastically with Jane of mass m. The conservation of momentum equation is established as Mv1 = (M + m)v2, allowing for the calculation of v2 in terms of v1. Additionally, the kinetic energy at the bottom of the swing is converted into gravitational potential energy, leading to a relationship between the heights h and H. The key insight is that understanding the energy conversion simplifies finding the vertical distance between H and h.

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CandyApples
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Homework Statement


Tarzan mass M swings from a vine from rest at height H. At the bottom of the arc he picks up Jane of mass m in a perfectly inelastic collision. They reach a vertical height h. How far vertically above h is H?

Homework Equations


Pi = Pf
R = [tex]\Sigma[/tex]mr/[tex]\Sigma[/tex]m

The Attempt at a Solution


Using conservation of momentum:
Mv1 = (M + m)v2
Center of mass:
(MH + (m+M)h)/(m + M)

I feel as though these must somehow be related to find the distance, but after looking for quite some time now, no obvious correlations are coming. I would appreciate any help in getting me in the right direction. Thanks!
 
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CandyApples said:

The Attempt at a Solution


Using conservation of momentum:
Mv1 = (M + m)v2

So we can find v2 in terms of v1.

Can you find v1 in terms of H ? (think energy)

At the bottom of the arc, Tarzan has 0 potential energy and only kinetic energy. This kinetic energy is converted into gravitational potential energy to the height h.

Can you find a relation between h and H now?
 
Yes it is now much easier, thank you so much.
 

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