Conservation of momentum: Student walking on surfboard find resultant velocity

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The discussion revolves around applying the conservation of momentum to find the resultant velocity of a student walking on a surfboard. The initial momentum of the system, consisting of the student and surfboard, is calculated based on their combined mass and initial velocity. The student walks at a velocity of 1.9 m/s relative to the surfboard, which complicates the calculation of the surfboard's final velocity. Clarification is needed on whether to consider the resultant velocity of the student, the surfboard, or both. Ultimately, the initial momentum is not zero, as the system is already moving at 2 m/s, necessitating careful consideration of reference frames in the calculations.
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Homework Statement


A 55 kg student stands on a 4.6 kg surfboard moving at 2.0 m/s [E]. The student then walks with a velocity of 1.9 m/s [E] relative to the surfboard, relative to the water. Neglect Friction.

Answer: 0.25 m/s[E]

Homework Equations


m1vi1 + m2vi2 = m1vf1 + m2vf2

The Attempt at a Solution


m1= 55kg
m2= 4.6kg
vi1= ?
vi2= ?
vf1= ?
vf2= ?

How do I solve this? Please help me set up variables. Please and Thank you!
 
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Solve what? You haven't stated a problem. You titled this "find resultant velocity", but resultant velocity of what? The student or the surfboard?

You need to use "conservation of momentum". The initial momentum of the "student-surfboard" system is 0 and so remains 0. In particular, the center of mass of the system will not move. Where is the center of mass initially? How does the student's center of mass move relative to that? How does the surfboard's center of mass move?
 
He wasn't clear, but he's trying to solve for the final velocity of the surf board, because that's the only variable that's not given.

On the initial side of the equation, you have the student and surfboard moving together, so their velocity will be the same and their mass will be added. Using basic algebra, this turns m1vi1 + m2vi2 into vi(m1+m2).

^edit: surely the initial momentum isn't 0 except if it were measured by the student himself, but clearly this is a reference frame outside the system since the system's initial velocity is given as 2 m/s.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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