Conservation of Rotational Momentum and changes in Rotational Speed

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SUMMARY

The discussion focuses on the conservation of rotational momentum in a scenario where a blob of putty, weighing 0.040 kg, falls onto a spinning record. The record has a mass of 0.10 kg and an initial rotational speed of 4.5 rad/s, with a rotational inertia of 0.0005 kg*m². After the blob sticks to the record, the new rotational inertia is calculated to be 0.0009 kg*m², leading to a final rotational speed of 2.5 rad/s. The calculations demonstrate the application of the principle of conservation of angular momentum.

PREREQUISITES
  • Understanding of rotational inertia and its calculation (I = m(r²))
  • Familiarity with the concept of angular momentum conservation (Iwi = Iwf)
  • Basic knowledge of rotational motion and units of measurement in physics
  • Ability to perform calculations involving mass, distance, and rotational speed
NEXT STEPS
  • Study the principles of angular momentum in more complex systems
  • Learn about the effects of external forces on rotational motion
  • Explore real-world applications of rotational dynamics in engineering
  • Investigate the relationship between linear and angular velocity
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of rotational dynamics and momentum conservation.

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Homework Statement



There is a record spinning when a blob of putty falls vertically on its edge; which is .10m from the center. What is the rotational speed of the record after the blob sticks on it?

additional information:

mass of blob = .040kg
mass of record = .10kg
rotational inertia of record before collision = .0005kg*m^2
rotational speed before collision = 4.5 rad/s

Homework Equations



I = m(r^2)
Iwi = Iwf

I = Rotational Inertia
wi = Initial Rotational Velocity
wf = Final Rotational Velocity
r = distance from point of rotation to point of applied force

The Attempt at a Solution



(calculate new rotational inertia)
I = m(r^2)
= .040(.10^2) = .0004

.0004 + .0005 = .0009

(set initial momentum equal to final momentum and solve for Wf)
4.5(.0005) = I(Wf)
.00225 = .0009(Wf)
2.5 = Wf
 
Last edited:
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What you did looks fine. Don't forget the units on your final answer.
 
It was correct. I'll make sure to include units in the future. Thanks.
 

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