- #1

starstruck_

- 185

- 8

## Homework Statement

You decide to design a bicycle that will have only 3/4 of the angular momentum of the original wheel when both wheels are traveling along a road at the same velocity. The original wheel had a diameter of d

_{1}=37cm and rotational inertia of I

_{1}=0.32 m

^{2}kg. If your new wheel has a diameter of d

_{2}= 34cm, what is its rotational inertia?

**2. Relevant equation**

Angular momentum denoted by L.

L= wI (where w is the angular velocity, and I is the rotational inertia)

Rotational inertia of a ring = mR

^{2}.

w= v/r (where v is the linear velocity).

## The Attempt at a Solution

I know that the angular momentum for the new wheel is 3/4 of the first wheel, their linear velocities are the same, I need rotational inertia of the new wheel.

L

_{new wheel}= 3/4 (v/d

_{1}/2) * m*(d

_{2}/2)^2

I honestly have no clue where to start or go with this question, or whether I'm even using all of the required equations :(