Conservative Force: Is F Dependent on Velocity?

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SUMMARY

The discussion centers on the nature of conservative forces, specifically examining whether a force dependent on velocity, such as F = -av, can be classified as conservative. It is established that velocity-dependent forces are generally not conservative, with the Lorentz force being a notable exception. The work done by such forces varies with the path taken, as illustrated by examples showing different work outputs for the same endpoints but different velocities. A conservative force is defined as one where the work done in a closed loop is zero.

PREREQUISITES
  • Understanding of classical mechanics and force concepts
  • Familiarity with the definition of conservative forces
  • Knowledge of the Lorentz force and its implications
  • Basic calculus for integrating force equations
NEXT STEPS
  • Study the properties of conservative and non-conservative forces in classical mechanics
  • Learn about the Lorentz force and its applications in electromagnetism
  • Explore the concept of work and energy in physics
  • Investigate the role of path dependence in force fields
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Physics students, educators, and professionals interested in classical mechanics, force analysis, and the distinctions between conservative and non-conservative forces.

johann1301
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If F is a force acting on a atom and is dependent on the velocity of the atom. Is the force conservative?
 
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What do you think -- what is the definition of a conservative force?
 
Velocity dependent forces are generally not conservative and exception is the Lorentz force due to a magnetic field acting on a charged particle although some would strictly speaking not consider this force conservative either.
 
Lets say

F=-av

If i integrate this, isn't it soley dependent on the start and end point? And thus, its conservative..?
 
a is just a constant.
 
V is dependent of time since v = a*t = m*a. Isn't it clear therefore that the work in reaching a specific position will depend on the path traveled. The longer the path the more time and thus more work.
 
my a is the acceleration due to the force
 
johann1301 said:
Lets say

F=-av

If i integrate this, isn't it soley dependent on the start and end point? And thus, its conservative..?
Certainly not. Consider ##a=-1 \; N/(m/s)## and an object which goes out a distance of 1 m at 1 m/s and then back at 1 m/s and another which goes out the same 1 m distance at 1 m/s and then back at 10 m/s. The force does 2 J of work for the first path and 11 J of work for the second. Furthermore, the work is non-zero, so both differ from the path which just stays at the endpoints.
 
gleem said:
Velocity dependent forces are generally not conservative and exception is the Lorentz force

... or any other force always acting perpendicular to velocity (e.g. coriolis force).
 
  • #10
Are you asking if force is always conserved? From my understanding yes f=mv thus it will always equation out to your mass and velocity on the other side of the equals sign?
 
  • #11
audire said:
Are you asking if force is always conserved? From my understanding yes f=mv thus it will always equation out to your mass and velocity on the other side of the equals sign?
That is not at all what is being asked.

A force is "conservative" if the work done on an object by that force as it moves along any path that loops back to where it started is always equal to zero. Note that in this context we are talking about a force "field" as in http://en.wikipedia.org/wiki/Field_(physics)
 

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