Consider a planet in some solar system which has a mass double

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SUMMARY

The discussion focuses on calculating the weight of an object on a hypothetical planet with double the mass of Earth while maintaining the same density. The key equations utilized include W=mg and g=GM/R², where M is mass and R is radius. The gravitational acceleration on the new planet is expressed as g = Y × (GMEarth/REarth²), with Y representing the multiplicative factor derived from the ratio of the radii. The conclusion confirms that the gravitational acceleration can be determined using these relationships, leading to a definitive understanding of weight on the new planet.

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draotic
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Homework Statement


Consider a planet in some solar system which has a mass double the mass of Earth and same density as of Earth . What is the weight of object on the planet in terms of 'W' , where 'W' is weight of object on Earth


Homework Equations


W=mg ... density = M / V . ... g=GM/R2


The Attempt at a Solution


since they both have same density..
i equated their M/V ratios and it gets me the ratio of their radii ..
but it still gets me nowhere
 
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Letting 'D' indicate the information you know for the double sized planet, you know

M_{D} = 2M_{Earth}

and you know R_{D} = X R_{Earth} where X is whatever you determined the ratio between the radii are. So simply find what the gravitational acceleration on this new planet will be with g = {{GM}\over{R^2}}. The trick will be being able to write 'g' as g = Y \times {{GM_{Earth}}\over{R_{Earth}^2}} where you have some constant, 'Y', multiplying the original values known for the Earth. Those known values you know gives g_{Earth} = 9.8 m/s.

You'll have some multiplicative value in front that will tell you how many times stronger or weaker the gravity is.
 


Pengwuino said:
Letting 'D' indicate the information you know for the double sized planet, you know

M_{D} = 2M_{Earth}

and you know R_{D} = X R_{Earth} where X is whatever you determined the ratio between the radii are. So simply find what the gravitational acceleration on this new planet will be with g = {{GM}\over{R^2}}. The trick will be being able to write 'g' as g = Y \times {{GM_{Earth}}\over{R_{Earth}^2}} where you have some constant, 'Y', multiplying the original values known for the Earth. Those known values you know gives g_{Earth} = 9.8 m/s.

You'll have some multiplicative value in front that will tell you how many times stronger or weaker the gravity is.

thanks , got it
 

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