"gregory"'s incorrect and irrelevant disproof of Gagnon
I will divide this into two parts:
1. In the first part I will show that "gregory's" disproof of Gagnon is both incorrect and irrelevant.
2. Once we agree that point 1 has been demonstrated , I will show that Gagnon et. al did their calculations for the boundary conditions of their partial differential equation correctly.
Here goes part 1:
gregory_ said:
No. One way speed measurements are not valid.
B] The Lorentz force law is different. I have shown that.
1. While this is true, it will turn out to be irrelevant. Which nullifies your attack from the start.
The main reason is that the Lorentz force mixes E and H (B) in the same formula which turms out to mess up your proof.
gregory_ said:
The boundary conditions on a metal are such that: there is no force on charges in the material, there can only be a force on the surface charges perpendicular to the surface. Because the Lorentz force law normally looks like \vec{F} = q(\vec{E} + \vec{v} \times \vec{B}) this is equivalent to the boundary condition on the fields of \bf{E}_\parallel=0, \bf{B}_\perp=0.
2. This is both irrelevant AND incorrect.
The mode you are describing is TEM: \bf{E}_\parallel=0, \bf{B}_\perp=0, a mode that is NOT used by the paper and a mode that is most never used in practice. At this point your counter is NULLIFIED as IRRELEVANT.
The waveguide mode used by Gagnon is TE (page 1768 bottom). This mode has ONLY the boundary condition \bf{E}_\parallel=0, there is no boundary condition for \bf{B}_\perp
The TE mode DOES not have any boundary condition on B (this is why it is called TE). Another mode, TM has the boundary condition \bf{B}_\perp=0. This mode is NOT used in the experiment.
For detailed explanations on wave guide theory see [1]
gregory_ said:
Because the force law is not the same in GGT frames, the boundary condition is not the same either.
3. This statement is incorrect and irrelevant as well. First off, since E and H are mixed together in the expression of the Lorentz force, you cannot draw the conclusion that E,H do not conserve form under transformation just because the Lorentz force doesn't.
Either way, the Lorentz force is not the issue. Conservation of the condition \bf{E}_\parallel=0 AT THE BOUNDARY is the ONLY ONE. And Gagnon et. al treated the boundary condition \bf{E}_\parallel=0 correctly.
This will be demonstrated in a separate post once we get agreement on this post.
gregory_ said:
Summary:
The calculations in the Gagnon experiment have been shown to be wrong on their starting assumptions. They are wrong.
Turns out that "gregory"'s disproof is both incorrect and irrelevant.
In the second post, I will show that Gagnon did his calculations correctly - you need to respect him and the reviewers of Phys Rev D more.
[1] Fundamentals of Electromagnetics with Engineering Applications – Stuart M. Wentworth (p338-355)