1. The problem statement, all variables and given/known data A train pulls away from a station with a constant acceleration of 0.40 m/s^2. A passenger arrives at a point next to the track 6.0 s after the end of the train has passed the very same point. What is the slowest constant speed at which she can run and still catch the train? On a single graph, plot the position versus time curves for both the train and the passenger. 2. Relevant equations x-train(t)=.20t^2 x-passenger(t)=vt+x_o 3. The attempt at a solution I initially supposed that x-train=x-passenger at t=6.0 s but that's clearly wrong. The answer at the back of the book is that v=4.8 m/s but I'm not sure why.