(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A train pulls away from a station with a constant acceleration of 0.40 m/s^2. A passenger arrives at a point next to the track 6.0 s after the end of the train has passed the very same point. What is the slowest constant speed at which she can run and still catch the train? On a single graph, plot the position versus time curves for both the train and the passenger.

2. Relevant equations

x-train(t)=.20t^2

x-passenger(t)=vt+x_o

3. The attempt at a solution

I initially supposed that x-train=x-passenger at t=6.0 s but that's clearly wrong. The answer at the back of the book is that v=4.8 m/s but I'm not sure why.

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# Homework Help: Constant acceleration problem with two objects

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