1. The problem statement, all variables and given/known data 2. A train pulls away from a station with a constant acceleration of 0.40 m/s. A passenger arrives at a point next to the track 6.0 s after the end of the train has started from rest at that very same point. What is the minimum constant speed at which she can run and still catch the train? On a single graph, plot the position versus time curves for both the train and the passenger. 2. Relevant equations x(t)=x0+v0t+1/2at2 v(t)=v0+at v2-v02=2aΔx v (average) = v0+v(t)/2 3. The attempt at a solution I'm having a heck of a time trying to understand the correct way to set this problem up. I know that we need to find the constant speed of the passenger. I also know that the position and velocity of the train need to be solved relative to the position of the passenger and then we set figure out how fast the passenger needs to move relative to the train. For the train, I know we solve for its position from the equation: x(t)=x0+v0t+1/2at2 I know we also need to solve for the postion of the passenger. However, this is where I'm stuck. I'm also confused as to how to properly set the train and passenger equal to one another to solve for the final speed of the passenger. Any help is very much appreciated.