Constant velocity and an object at rest

[Tiven white]

Homework Statement

True or False

The stresses on an object traveling at constant velocity are the same as the stresses on an object.at rest.

Homework Equations

F = m*a

The Attempt at a Solution

For both an object at constant velocity and an object at rest the acceleration is zero therefore by Newtons second law the force should be zero a stress is a force therefore I concluded that the stresses on an object at constant velocity and an object at rest is zero which is the same so I say the answer is true. Is this correct? any help would be appreciated.

 

[Tiven white]

Can someone please validate the solution I proposed to this question.

 

[PhanthomJay]

Homework Statement

True or False

The stresses on an object traveling at constant velocity are the same as the stresses on an object.at rest.

Homework Equations

F = m*a

The Attempt at a Solution

For both an object at constant velocity and an object at rest the acceleration is zero therefore by Newtons second law the force should be zero a stress is a force therefore I concluded that the stresses on an object at constant velocity and an object at rest is zero which is the same so I say the answer is true. Is this correct? any help would be appreciated.

Tiven
This question is a bit ambiguous. Newtons First Law states in effect that the net force acting on an object at rest or in motion at constant velocity is zero. But the problem asks about stresses, which are internal to the system and which are not zero, whether the object is at rest or in motion at constant velocity. If the object at constant velocity is subject to the same system of forces as at rest, the vector sum of which is zero, then the stresses, which are non-zero, are the same in both cases.

 

[CWatters]

Correct.

However you might want to state what assumptions you have made in giving your answer. Clearly the forces/stresses acting on a car aren't the same when it's moving or stationary.

 

[Tiven white]

Correct.

However you might want to state what assumptions you have made in giving your answer. Clearly the forces/stresses acting on a car aren't the same when it's moving or stationary.

There is no option to provide assumptions made on this question it is strictly true or false so
Could u clarify the last sentence In which u said the forces on a car is.not.the same when it is at rest and when it is moving at.constant.velocity. and make reference to the term ' stresses' when doing so. This would aid in clearing up any ambiguity of.whether false is an option .

 

[Tiven white]

Tiven
This question is a bit ambiguous. Newtons First Law states in effect that the net force acting on an object at rest or in motion at constant velocity is zero. But the problem asks about stresses, which are internal to the system and which are not zero, whether the object is at rest or in motion at constant velocity. If the object at constant velocity is subject to the same system of forces as at rest, the vector sum of which is zero, then the stresses, which are non-zero, are the same in both cases.

Though it is ambiguous what would be ur response regarding this question?

 

[CWatters]

I would answer true.

Could u clarify the last sentence In which u said the forces on a car is.not.the same when it is at rest and when it is moving at.constant.velocity

One example would be air resistance (eg drag). That would create stresses in various things. Most obvious would be the windscreen or other surfaces at the front, but also in the tyres (because the car has to overcome drag by "pushing the ground backwards").

So in answering true I would like to add an assumption that the object is moving in free space and not subject to, for example, air resistance.

 

[PhanthomJay]

Though it is ambiguous what would be ur response regarding this question?

My first inclination would be to answer TRUE, but the way the problem is worded, the answer is SOMETIMES. Which apparently is not an option. So I assume that the problem implies that the object is subject to the same set of forces in both cases.