Construct B field from a given E field using Maxwell's Eqns

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SUMMARY

The discussion focuses on deriving the magnetic field B(t,r) from a given electric field E(t,r) = (E0/c) (0, 0, y/t²) using Maxwell's equations in a vacuum. The relevant equations are simplified due to zero current density (J = 0) and charge density (ρ = 0), leading to the equations: Div(E) = 0, Div(B) = 0, Curl(E) = -∂B/∂T, and Curl(B) = μ0ε0∂E/∂t. The user successfully computes Curl(E) and sets up the relationship for ∂B/∂T, but faces challenges in integrating and applying boundary conditions to determine B. The conclusion emphasizes that the boundary condition B → 0 as t → ∞ eliminates the need for additional functions in the solution.

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Homework Statement


Given an electric field in a vacuum:
E(t,r) = (E0/c) (0 , 0 , y/t2)

use Maxwell's equations to determine B(t,r) which satisfies the boundary condition B -> 0 as t -> ∞

Homework Equations


The problem is in a vacuum so in the conventional notation J = 0 and ρ = 0 (current density is zero and charge density is zero). Maxwell's equations are reduced to:

Div(E) = 0
Div(B) = 0
Curl(E) = -∂B/∂T
Curl(B) = μ0ε0∂E/∂t

The Attempt at a Solution



I've been given E so taking the curl of it I get

Curl E = (E0/c) (t-2 , 0 , 0)

So using the third Maxwell Equation I get ∂B/∂T = -(E0/c) (t-2 , 0 , 0)

But this is a partial differential. When I integrate the components of the vector with respct to t, I have to add functions of x,y,z.

So B = E0/c (1/t + f(x,y,z) , g(x,y,z) , h(x,y,z) )

Taking the curl of this vector is tricky but I'll give it a go.

Setting the curl of my B vector above to equal ε0μ0E I get a big mess of partial derivatives of f(x,y,x), g(x,y,z) and h(x,y,z) equaling my original E vector, which two of its components are zero and one is yt-2

Help please?
 
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Why would you want to take the curl of B ?

And you have a boundary condition for B that gets rid of all these f, g and h
 
Oh of course. Since B tends to zero with long times, there can't be any steady B fields like f, g and h would necessitate. Thanks very much!
 

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