Construct using unmarked straight edge only

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This discussion focuses on constructing a line through an arbitrary point P that is parallel to a given line segment AB using only an unmarked straight edge. The midpoint M of AB is utilized in the construction process. Participants detail the steps to find intersection points X and Y, leading to the identification of point Z, which confirms that line PZ is parallel to AB. The construction ultimately connects point P to the harmonic conjugate of M on line AB, demonstrating a practical application of Ceva's theorem.

PREREQUISITES
  • Understanding of geometric constructions using straight edges
  • Familiarity with the concepts of midpoints and parallel lines
  • Knowledge of harmonic conjugates in projective geometry
  • Basic principles of Ceva's theorem
NEXT STEPS
  • Study the properties of harmonic conjugates in projective geometry
  • Explore advanced geometric constructions using unmarked straight edges
  • Learn about the applications of Ceva's theorem in various geometric contexts
  • Investigate the implications of parallel lines in Euclidean geometry
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Mathematicians, geometry enthusiasts, and educators interested in advanced geometric constructions and theorems related to parallel lines and harmonic conjugates.

caffeinemachine
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Let points $A$ and $B$ be given on the plane. The mid point of $A$ and $B$, call it $M$, is also given. Mark an arbitrary point $P$ on the plane. Using unmarked straight edge only, construct the line passing through $P$ and parallel to $AB$.
 
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caffeinemachine said:
Let points $A$ and $B$ be given on the plane. The mid point of $A$ and $B$, call it $M$, is also given. Mark an arbitrary point $P$ on the plane. Using unmarked straight edge only, construct the line passing through $P$ and parallel to $AB$.
View attachment 415

Draw a random line through $M$, meeting $AP$ at $X$, and $BP$ at $Y$. Let $Z$ be the point of intersection of $BX$ and $AY$. I'll leave you to figure out why $PZ$ is parallel to $AB$.

Hint: What this does is to construct the line connecting $P$ to the harmonic conjugate of $M$ on the line $AB$ (which happens to be the point at infinity).
 

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Opalg said:
https://www.physicsforums.com/attachments/412​
Draw a random line through $M$, meeting $AP$ at $X$, and $BP$ at $Y$. Let $Z$ be the point of intersection of $BX$ and $AY$. I'll leave you to figure out why $PZ$ is parallel to $AB$.

Hint: What this does is to construct the line connecting $P$ to the harmonic conjugate of $M$ on the line $AB$ (which happens to be the point at infinity).
Thank You. I can conclude now using Ceva's theorem.
 

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