Constructing Balanced Ionic Equations

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The discussion centers on balancing ionic equations, specifically for the half-reactions involving aluminum and hydrogen ions. The initial attempt at a solution proposes the equation 2Al + 6H^+1 → 2Al^+3 + 3H2. However, the book's answer suggests 4Al + 6H^+1 → 2Al^+3 + 3H2, which is claimed to be incorrect. The consensus is that the book's answer does not properly balance the equation. The correct balanced ionic equation is 2Al + 6H^+1 → 2Al^+3 + 3H2.
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Homework Statement


Write a balanced ionic equation for the half equations given below:
Al----> Al^+3 + 3e-
2H^+1 + 2e- -----> H2

Homework Equations

The Attempt at a Solution


I think the answer is:
2Al + 6H^+1 ----> 2Al^+3 + 3H2
But the answer in the book is:
4Al + 6H^+1 ----> 2Al^+3 + 3H2
What is the correct answer?
 
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Answer in the book is not correctly balanced - so it is wrong.
 
Thanks!
 

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