Continuity Equation: Relationship between vA and vB in terms of d and D

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SUMMARY

The discussion centers on the application of the continuity equation in fluid dynamics, specifically the relationship between velocities vA and vB in relation to the diameters d and D. Using the values d = 1 cm and D = 10 cm, the correct ratio of speeds is derived as vB/vA = 100, confirming that the velocity increases as the diameter decreases. The continuity equation is expressed as ρ1A1v1 = ρ2A2v2, where A is the cross-sectional area calculated using the formula A = π(Diameter²/4). The participant successfully resolves their initial confusion regarding the calculations.

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Homework Statement


The continuity equation provides a second relation between the vA and vB, this time in terms of the diameters d and D. Numerical check: If the diameters are d = 1 cm and D = 10 cm, what is the ratio of the speeds, vB/vA?

Homework Equations


To clarify, is both d and D diameters, just one's capitalized to show the difference between the two?
The continuity equation is: Δm=ρV=ρAvΔt
my notes show: ρ2A2v2 = ρ1A1v1
Am I reading correctly that:
ρ=density
A= cross-sectional area (equal to ∏(Diameter^2/4))?
v= velocity/speed

The Attempt at a Solution


A1v1=A2v2 ===> v2=v1(A1/A2) ====> v2=v1(d1^2/d2^2) ===>
Plugging this into the above given information:
v2= v1(10cm^2/1cm^2) = v1(100cm)
v1 = v2 (1cm^2/10cm^2) = v2(.01cm)
So the ratio of speeds would be .01cm/100cm = .0001
I know I'm doing something wrong, but this is all I have in my notes that looks somewhat useable. Please help! Thank you!
 
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Wow, after typing that all out I was seeing what I was doing wrong. I've got it figured out now. :)
 

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