Contour integral (please check my solution)

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SUMMARY

The discussion focuses on evaluating a contour integral, specifically addressing the path defined by the points from \( e^{-i\pi/2} \) to \( e^{i\pi/2} \) on the unit circle. The user confirms that the contour \( C \) starts at \( -i \) and ends at \( i \), which is crucial for understanding the limits of integration from \(-\pi/2\) to \(\pi/2\). The simplification of the integral is also highlighted by noting that \( \sin\pi = 0 \), which plays a significant role in the evaluation process.

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  • Familiarity with the unit circle in the complex plane
  • Knowledge of trigonometric identities, specifically \( \sin \) functions
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aruwin
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Hello. Can someone check my solution for this question? I am not sure what to do about the "from e^-pi*1/2 to e^pi*i/2" part. I ignored that part.
 

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That looks correct. You could simplify the answer by noticing that $\sin\pi = 0.$
 
Opalg said:
That looks correct. You could simplify the answer by noticing that $\sin\pi = 0.$

Thanks. But what does "from e^-pi*1/2 to e^pi*i/2" mean?
 
aruwin said:
Thanks. But what does "from e^-pi*1/2 to e^pi*i/2" mean?
It means that $C$ is the contour starting at the point $e^{-i\pi/2} = -i$ on the unit circle, and ending at the point $e^{i\pi/2} = i.$
 
Opalg said:
It means that $C$ is the contour starting at the point $e^{-i\pi/2} = -i$ on the unit circle, and ending at the point $e^{i\pi/2} = i.$

Does that affect the calculation here? Is that why we integrate from -pi/2 to pi/2?
 

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