Contour integral (please check my solution)

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Discussion Overview

The discussion revolves around a contour integral solution, specifically addressing the interpretation of the contour limits "from e^-pi*1/2 to e^pi*i/2" and its implications for the calculation involved.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant requests verification of their solution and expresses uncertainty about the contour limits.
  • Some participants affirm the correctness of the solution while suggesting simplifications based on the property that $\sin\pi = 0$.
  • Another participant seeks clarification on the meaning of the contour limits and their impact on the calculation.
  • It is explained that the contour starts at $e^{-i\pi/2} = -i$ and ends at $e^{i\pi/2} = i$ on the unit circle.
  • A participant questions whether the contour limits affect the calculation and why integration occurs from -pi/2 to pi/2.

Areas of Agreement / Disagreement

Participants generally agree on the correctness of the solution but have differing views on the implications of the contour limits and their effect on the integration process. The discussion remains unresolved regarding the impact of these limits on the calculation.

Contextual Notes

There are unresolved questions about the significance of the contour limits and their relationship to the integration bounds, which may depend on specific definitions or interpretations of the contour integral.

aruwin
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Hello. Can someone check my solution for this question? I am not sure what to do about the "from e^-pi*1/2 to e^pi*i/2" part. I ignored that part.
 

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That looks correct. You could simplify the answer by noticing that $\sin\pi = 0.$
 
Opalg said:
That looks correct. You could simplify the answer by noticing that $\sin\pi = 0.$

Thanks. But what does "from e^-pi*1/2 to e^pi*i/2" mean?
 
aruwin said:
Thanks. But what does "from e^-pi*1/2 to e^pi*i/2" mean?
It means that $C$ is the contour starting at the point $e^{-i\pi/2} = -i$ on the unit circle, and ending at the point $e^{i\pi/2} = i.$
 
Opalg said:
It means that $C$ is the contour starting at the point $e^{-i\pi/2} = -i$ on the unit circle, and ending at the point $e^{i\pi/2} = i.$

Does that affect the calculation here? Is that why we integrate from -pi/2 to pi/2?
 

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