Contour integral using branchcut

Click For Summary
SUMMARY

The forum discussion centers on computing the integral of e^(-x) / (x-1) using contour integrals, specifically addressing the calculation of residues at x = 1. The user identifies the integral as I = e^(-1) / (2) pi i, but acknowledges potential errors in their approach. They utilize a branch cut along the real positive axis and express confusion regarding the correct contour to apply. Additionally, they seek assistance with implementing LaTeX code for mathematical expressions in the forum.

PREREQUISITES
  • Understanding of complex analysis and contour integration
  • Familiarity with residue theorem and its application
  • Knowledge of branch cuts in complex functions
  • Experience with exponential integrals and their properties
NEXT STEPS
  • Study the residue theorem in complex analysis
  • Learn about branch cuts and their implications in contour integration
  • Explore the properties of exponential integrals in depth
  • Research how to use LaTeX for mathematical notation in online forums
USEFUL FOR

Mathematicians, physicists, and students engaged in complex analysis, particularly those working with contour integrals and residue calculations.

qlsn4123
Messages
2
Reaction score
0
I want to compute kind of following problems.

int(from 0 to infinity) e^(-x) / (x-1) dx= I

using contour integrals, then

2 pi i I = -pi i / (2) Res[e^(-x) ln(x) /(x-1) , x = 1] - pi i / (2) Res[e^(-x) /(x-1) (ln(x) + 2 pi i) , x = 1]

I = e^(-1) / (2) pi i

I know there is some error... so, what is the problem, I mean that how could I solve this problem?.. please help me~
 
Last edited:
Physics news on Phys.org
What kind of contour are you using?
 
I use the branch cut~, real positive axis.

I know that the integrant is kind of exponential integrals.

Actually I try to solve following integral.

I(V, H) = int(from 0 to infinity) { 1 / (k sinh kH - cosh kH) - 2 e^(-kH) / (k - 1) } * (k + 1) * cosh(kV) * e^(-kH) dk

ps. How could I use "Latex code" in this forums? It is not work.. [tex]\int [\tex]..<br /> <br /> thank you.[/tex]
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K