Converge absolutely or conditionally, or diverges?

  • Thread starter Thread starter rcmango
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around determining the convergence behavior of a series involving the tangent function, specifically whether it converges absolutely, conditionally, or diverges. The series is related to concepts such as alternating series and harmonic series.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the behavior of tan(1/n) as n approaches infinity and its relevance to the convergence of the series. There are questions about the conditions for convergence and the criteria for absolute convergence.

Discussion Status

Some participants have offered insights regarding the criteria for alternating series and the need to check for absolute convergence. There is an ongoing exploration of the implications of the series' behavior and the conditions under which it converges.

Contextual Notes

Participants are navigating assumptions about the series' convergence and discussing the relevance of specific tests, such as the Leibniz test for alternating series. There is a noted lack of consensus on certain interpretations and the implications of the series' behavior as it approaches infinity.

rcmango
Messages
232
Reaction score
0

Homework Statement



Determine if the series converges absolutely, converges conditionally, or diverges.

equation is here: http://img409.imageshack.us/img409/7353/untitledly5.jpg

Homework Equations



maybe alternating series, or harmonic series?

The Attempt at a Solution



not real familiar with tan with series.
haven't tried much, need supporting work for the answer.
need help.
 
Last edited by a moderator:
Physics news on Phys.org
As n-> infinity, tan(1/n) -> tan(0) -> 0
Does this help?
 
Actually, this says nothing at all about the series. The implication is one way only: "Sum a_n converges ==> a_n-->0" but "a_n-->0 ==> nothing".

Actually the series satisfies all the criteria corresponding to the convergence of an alternating series. Remains to see if it converges absolutely. I.e. does

[tex]\sum_{n=1}^{\infty}\tan(n^{-1})<\infty[/tex]

??
 
no it doesn't converge absolutely because it continues on to infinity.

however, i do ask, how do you know to test it to be less than infinity? in other words, the convergence for a alternating series passes. but what other series convergence did not pass?

so ultimately, this will converge conditionally.

for my work, i could prove this by showing the alternating series? and then showing that it also continues on to infinity?

thanks again for all the help so far.
 
What do you mean by "continues on to infinity" ?
 
rcmango, i think you mean using the Leibniz test (for alternating series)
there are three conditions, check all to prove.
 
chanvincent said:
As n-> infinity, tan(1/n) -> tan(0) -> 0
Does this help?
It is more to the point that tan(1/n) is decreasing. Knowing that it goes to 0 is neither necessary nor helpful.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
1K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K