Converge absolutely or conditionally, or diverges?

  • Thread starter Thread starter rcmango
  • Start date Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 3K views
rcmango
Messages
232
Reaction score
0

Homework Statement



Determine if the series converges absolutely, converges conditionally, or diverges.

equation is here: http://img409.imageshack.us/img409/7353/untitledly5.jpg

Homework Equations



maybe alternating series, or harmonic series?

The Attempt at a Solution



not real familiar with tan with series.
haven't tried much, need supporting work for the answer.
need help.
 
Last edited by a moderator:
Physics news on Phys.org
As n-> infinity, tan(1/n) -> tan(0) -> 0
Does this help?
 
Actually, this says nothing at all about the series. The implication is one way only: "Sum a_n converges ==> a_n-->0" but "a_n-->0 ==> nothing".

Actually the series satisfies all the criteria corresponding to the convergence of an alternating series. Remains to see if it converges absolutely. I.e. does

[tex]\sum_{n=1}^{\infty}\tan(n^{-1})<\infty[/tex]

??
 
no it doesn't converge absolutely because it continues on to infinity.

however, i do ask, how do you know to test it to be less than infinity? in other words, the convergence for a alternating series passes. but what other series convergence did not pass?

so ultimately, this will converge conditionally.

for my work, i could prove this by showing the alternating series? and then showing that it also continues on to infinity?

thanks again for all the help so far.
 
rcmango, i think you mean using the Leibniz test (for alternating series)
there are three conditions, check all to prove.