Convergence of ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}##

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SUMMARY

The sequence of positive integer powers of the sinc function, denoted as ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}##, converges pointwise to the indicator function ##\mathbf{1}_{\{0\}}(x)##. However, this convergence is not uniform due to the discontinuity of the indicator function. The uniform convergence theorem indicates that for uniform convergence to occur, the limit function must be continuous, which is not the case here. Therefore, the sequence does not exhibit uniform convergence.

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Wuberdall
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Hi Physics Forums,

I have a problem that I am unable to resolve.

The sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## of positive integer powers of ##\mathrm{sinc}(x)## converges pointwise to the indicator function ##\mathbf{1}_{\{0\}}(x)##. This is trivial to prove, but I am struggling to decide if the convergence is uniform or not.

I hope that someone in here can help me, either by providing a reference or a sketch proof.

Thanks in regards.
 
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Wuberdall said:
Hi Physics Forums,

I have a problem that I am unable to resolve.

The sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## of positive integer powers of ##\mathrm{sinc}(x)## converges pointwise to the indicator function ##\mathbf{1}_{\{0\}}(x)##. This is trivial to prove, but I am struggling to decide if the convergence is uniform or not.

I hope that someone in here can help me, either by providing a reference or a sketch proof.

Thanks in regards.
What does the uniform convergence theorem say about continuous functions?
 
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haruspex said:
What does the uniform convergence theorem say about continuous functions?
Thanks,

Each of the ##\mathrm{sinc}^n(x)## functions in the sequence are continuous. Thus IF the sequence where to converge uniformly to ##\mathbf{1}_{\{0\}}##, then ##\mathbf{1}_{\{0\}}## has to be continuous (which it is not). Consequently, the sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## is not uniformly converging.
 
Wuberdall said:
Thanks,

Each of the ##\mathrm{sinc}^n(x)## functions in the sequence are continuous. Thus IF the sequence where to converge uniformly to ##\mathbf{1}_{\{0\}}##, then ##\mathbf{1}_{\{0\}}## has to be continuous (which it is not). Consequently, the sequence ##\{\mathrm{sinc}^n(x)\}_{n\in\mathbb{N}}## is not uniformly converging.
Quite so.
 
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