Convergence of Series: Understanding the Limit Comparison Test

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Homework Help Overview

The discussion revolves around the convergence of the series \(\sum \frac{1}{2n + 3}\) as \(n\) approaches infinity. Participants are exploring the Limit Comparison Test and its application to determine the behavior of the series in question.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the Comparison Test and subsequently the Limit Comparison Test, questioning the implications of their results. Other participants suggest considering different series for comparison and explore the outcomes of the tests.

Discussion Status

There is an ongoing exploration of the Limit Comparison Test, with some participants affirming its validity while others raise questions about the implications of inconclusive results. Multiple interpretations of the tests and their outcomes are being discussed.

Contextual Notes

Participants are navigating the limitations of the Comparison Test and the conditions under which the Limit Comparison Test can be applied, particularly regarding the positivity of terms and the nature of the limits obtained.

Sabricd
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Hello,

I need help with problem.
Would you mind solving it so I can compare it with my answer?
\sum 1/(2n + 3) where n=1 and goes to infinity.

First of all, I got for an= 1/(2n + 3) and for bn= 1/2n
By using the comparison Test I got:

1/(2n + 3) < (1/2n)

and (1/2n) is a familiar divergent harmonic series. Hence an should also be divergent, but no because bn is larger than an...so the Comparison Test does not determine whether or not the series is divergent, so I have to use the Limit Comparison Test.

Well when I did the Limit Comparison Test I eventually got the limit as n goes to infinity of 2/(2 + (3/n)) which equals 1...and one is more than zero, hence by the limit comparison test either both series converge or diverge...but what do I do now...Please correct me if I'm wrong!

I would deeply appreciate the help!
Thanks! :)
 
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Well, comparing to 1/(2n) didnt work. Maybe you'll need to compare it to another series. Maybe make the 2 larger?
 
Well I have looked at my notes and previous homework. Is it possible...after your comparison test fails to do the limit comparison and if the answer is greater than 0, and therefore both sequences might or might not converge, to go back and test bn?
For instance the problem above ended up being divergent by following that logic and I seem to find the same logic for all my other homework problems. Am I wrong?
 
I'm sorry, I didn't read your first post completely. You are correct, the limit comparison test works just fine. And you can indeed conclude that the series diverges...
 
But what happens if your comparison test fails and you limit comparison test is negative or zero? Does that ever happen?
 
Well, the test can't be negative, since the test is only applicable to series with positive terms.
If you get zero or infinity, then the test is inconclusive, you'll have to try something else then. Maybe try another limit comparison test, but compare with another series...
 

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