Convergent and Divergent problem

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SUMMARY

The discussion centers on the convergence properties of sequences defined by the equation (a_n + b_n)^n = c_n, where a_n is convergent and b_n is divergent. It concludes that c_n is divergent when a_n is convergent and b_n is divergent, but no definitive rule or theorem is provided for the case when both a_n and b_n are divergent. The participants suggest exploring epsilon-delta proofs to analyze convergence, indicating that no conclusive determination can be made regarding c_n's convergence in these scenarios.

PREREQUISITES
  • Understanding of convergence and divergence in sequences
  • Familiarity with epsilon-delta proofs in calculus
  • Knowledge of sequence notation and limits
  • Basic principles of mathematical analysis
NEXT STEPS
  • Research epsilon-delta proofs in detail
  • Study convergence tests for sequences and series
  • Explore the properties of convergent and divergent sequences
  • Investigate the implications of combining convergent and divergent sequences
USEFUL FOR

Mathematics students, educators, and anyone studying sequences and series in mathematical analysis will benefit from this discussion.

danni7070
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If I have (a_n + b_n)^n = c_n where a_n is convergent and b_n divergent. Is c_n then divergent?

And what if a_n and b_n were divergent, would c_n be divergent also?

but what if they were both convergent then surely c_n is convergent right?

I can't see a rule or a theorem that tells me this is correct and frankly it is getting on my nerve.

Somebody here who knows? :smile:

Thanks.
 
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Hve u tried an epsylon- delta proof? I think it might work.
 
No conclusion is possible for the convergence of c_n.

a_n=b_n=0
a_n=b_n=1
a_n=0, b_n=(-1)^n \times \frac{1}{4}
a_n=1, b_n=(-1)^n
a_n=b_n=(-1)^n
a_n=b_n=(-1)^n \times \frac{1}{4}
 

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