Convergent limits for sequences: picture terms

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SUMMARY

A sequence is convergent if, for any value of K, there exists an N such that for all n greater than N, the terms an are either greater than K or less than -K. In the context of the sequence a(n) = 2n, when n = 2, an equals 4. The terms K and N represent thresholds for convergence, with K being a limit and N indicating the point beyond which all terms of the sequence fall within the defined bounds. Graphically, K and N can be represented on the vertical and horizontal axes, respectively, with large circles drawn around the limits to indicate convergence towards ∞ or -∞.

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  • Understanding of sequence limits in calculus
  • Familiarity with the concepts of convergence and divergence
  • Knowledge of graphing functions and sequences
  • Basic mathematical notation involving K, N, an, and n
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  • Study the definition and properties of convergent sequences in calculus
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939
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A limit of a sequence is definitely convergent if:

If for any value of K there is an N sufficiently large that an > K for n > N, OR for any value of K there is an N sufficiently large that an<±K for n > N

My only question is what exactly are K, N, an and n? What values are they? How would they be graphed? I.e. for the sequence a(n) = 2n

n = 2
an = 4
What are K and N? Are they on the horizontal or vertical axis?
 
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hi 939! :smile:
939 said:
A limit of a sequence is definitely convergent if:

My only question is what exactly are K, N, an and n? What values are they? How would they be graphed?

nooo, you mean definitely divergent :biggrin:

essentially, it means that the sequence converges to ∞, or to -∞

we can't use δ and ε for ∞ (because we can't get close enough to ∞ !)

so instead of small circles round the limit, we draw large circles round the limit (∞), ie x > K (or x < -K), and we say that that large circle has to contain all an once n is large enough

it's the same as saying that the sequence {1/an} has the limit 0 (from above, for the ∞ case) (or from below, for the -∞ case)​
 
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