Converging Lens Homework: Finding Image Distance with Thin Lens Equation"

  • Thread starter Thread starter aChordate
  • Start date Start date
  • Tags Tags
    Converging Lenses
AI Thread Summary
The discussion revolves around calculating the image distance for a new converging lens with a focal length of 32.0 cm, given an initial lens with a focal length of 11.0 cm that produced a real image at 25.0 cm. Using the thin lens equation, the object distance was determined to be 0.196 m for the first lens. For the second lens, the calculations yielded an image distance of -0.506 m, indicating a virtual image. Participants noted the importance of maintaining significant figures in calculations to improve accuracy. The final consensus is that the image produced by the second lens is virtual.
aChordate
Messages
76
Reaction score
0

Homework Statement



An object is in front of a converging lens with a focal length of 11.0 cm. The lens
produces a real image located 25.0 cm from the lens. If the lens is replaced by a new lens
(in the same position) that has a focal length of 32.0 cm, what is the image distance of the
new lens? Is the image real or virtual?

Homework Equations



Thin lens equation
1/f=1/d0+1/di

The Attempt at a Solution



lens 1:

1/+11*10-2=1/dO+1/+25.0*10-2

dO=0.196m

lens2:

1/+32.0*10-2=1/0.196m+1/di

di=-0.506m

Virtual image
 
Physics news on Phys.org
aChordate said:


lens 1:

1/+11*10-2=1/dO+1/+25.0*10-2

dO=0.196m

lens2:

1/+32.0*10-2=1/0.196m+1/di

di=-0.506m

Virtual image


Your approach is correct.

Your answer is pretty close, but there are some rounding errors. You might want to try again, but keep more significant figures in the intermediate steps.
 
  • Like
Likes 1 person
I got -.509 on the second try. Hopefully that is correct.
 
aChordate said:
I got -.509 on the second try. Hopefully that is correct.
Yup. :approve: (Don't forget your units though.)
 
  • Like
Likes 1 person

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Analyzing this 2-lens optical system
Replies
5
Views
1K
Find the location and length of the final image
Replies
2
Views
890
Focal length of the eyepiece lens in a compound microscope
Replies
7
Views
1K
Inserting thick lenses into a thin lens system and deducing values
Replies
1
Views
2K
Optics Problem with a Double Lens System
Replies
1
Views
2K
Mirror placed horizontally between two half convex lenses
Replies
11
Views
1K
Convergent lenses and calculating image position
Replies
2
Views
1K
Splitting of a convex lens problem
Replies
5
Views
2K
Microscope converging lens problem
Replies
3
Views
3K
Geometric optics: Thin lense equation
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top