Splitting of a convex lens problem

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Homework Help Overview

The problem involves a thin convex lens with a focal length of 20 cm that has been split into two parts along the principal axis, creating a gap of 2 mm between the halves. An object is placed 10 cm from the lens, and the question pertains to the distance between the two virtual images formed by the split lens.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of splitting the lens and how it affects the focal length and image formation. There are questions about the correct interpretation of the image distances for each half of the lens and the direction of the distance between the images. Some participants suggest making sketches to clarify the setup.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. There is an emphasis on visualizing the setup and understanding the relationship between the object, the lens, and the resulting images. Guidance has been offered to create sketches to aid in understanding the situation.

Contextual Notes

There is uncertainty regarding the definition of the axes involved and how the images relate to the original principal axis after the lens is split. Participants are encouraged to clarify these aspects through visual representation.

Krushnaraj Pandya
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Homework Statement


A thin convex lens of focal length 20 cm is split into two parts along the principal axis, now there is a 2mm gap between the top and bottom parts, an object O is placed at 10 cm from the lens, the distance between the two virtual images will be?

Homework Equations


1/v - 1/u =1/f

The Attempt at a Solution


Cutting along principal axis, focal length remains same. Using lens formula I got v= -20, I think this will then act as an object but using this value gives v2=infinity which isn't correct- how do I proceed?
 
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v = -20 for the upper half, or for the lower half ? :rolleyes:
Make a sketch ...
 
Krushnaraj Pandya said:
the distance between the two virtual images
What do you think this refers to? In which direction is this distance?
 
BvU said:
v = -20 for the upper half, or for the lower half ? :rolleyes:
Make a sketch ...
haruspex said:
What do you think this refers to? In which direction is this distance?
Ok, so the distance is the gap along y-axis The magnification is 2 but I'm confused whether the base of the two images will be on the old principal axis or along the horizontal line containing the straight horizontal part of the half-lens. I suppose if it were on the old axis, there'd be no distance so it has been shifted along with the lens which would give the answer as 2mm but how these images are getting separated just isn't clicking in my mind and I'm having trouble even trying to think how to make a sketch
 
Krushnaraj Pandya said:
Ok, so the distance is the gap along y-axis
You don't give us a clue what axis that is.
You also don't post a sketch for good reasons:
Krushnaraj Pandya said:
I'm having trouble even trying to think how to make a sketch
because I suspect you can't make sense of
Krushnaraj Pandya said:
is split into two parts along the principal axis
So let's start with a sketch of the situation before the splitting. Can you post that and make clear what the principal axis is ?
 
Krushnaraj Pandya said:
whether the base of the two images will be on the old principal axis or along the horizontal line containing the straight horizontal part of the half-lens.
Or maybe neither.
If you follow a ray from where the object sits on the principal axis through the middle of the lens, where does it meet the image?
When the lens is split there are two copies of the old middle. If you now draw the rays to each of these points, where do they meet the respective images?
 

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