Converging lens solve for all variables given f, Hi, and Ho

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Homework Help Overview

The discussion revolves around a problem involving a converging lens, where the focal length (f) is given as 1.43m, and the image height (Hi) is 2m. Participants are tasked with finding various variables related to the lens, including the object height (Ho) and distances (do and di).

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the object height and image height through magnification, noting that the image is 20 times smaller than the object. There are attempts to express object distance in terms of image distance and to manipulate the lens formula to isolate variables.

Discussion Status

There are multiple lines of reasoning being explored regarding the relationships between the variables. Some participants suggest using magnification to derive relationships, while others are working through the lens formula to find object distance. Guidance has been offered on how to manipulate the equations, but no consensus has been reached on the final values.

Contextual Notes

Participants are working under the constraints of the given values and the relationships defined by the lens equations. There is some uncertainty regarding the derivation of object distance and the use of magnification in the context of the problem.

Samr28
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Homework Statement


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What is directly given in the problem:
Converging lens with f=1.43m
Hi = 2m

Homework Equations



Hi/Ho = di/do
M = Hi/Ho = di/do
1/f = 1/do + 1/di

The Attempt at a Solution



Ho = 2m * 20 = 40m
Not sure how I can get do from this. All of the equations seem to need di.
 
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Samr28 said:

Homework Statement


[/B]
View attachment 200090

What is directly given in the problem:
Converging lens with f=1.43m
Hi = 2m

Homework Equations



Hi/Ho = di/do
M = Hi/Ho = di/do
1/f = 1/do + 1/di

The Attempt at a Solution



Ho = 2m * 20 = 40m
Not sure how I can get do from this. All of the equations seem to need di.
You can get the object height from the magnification. Since the image is 20 times smaller than the object, M=1/20. We also know that H_i=2 \, m.

To get the distance to the coaster, multiply \frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i} through by d_o and substitute 1/M=20 for d_o/d_i. You know the focal length, so it shouldn't be difficult to solve for d_o from there.
 
the image is 20x smaller than the object so

hi = 1/20 ho

giving us

hi/ho = 1/20

but hi/ho = di/do

so we also have that

di/do = 1/20

so that we have that the object distance in terms of the image distance is

do = ... ?
 
andrevdh said:
the image is 20x smaller than the object so

hi = 1/20 ho

giving us

hi/ho = 1/20

but hi/ho = di/do

so we also have that

di/do = 1/20

so that we have that the object distance in terms of the image distance is

do = ... ?
Multiply the equation \frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i} through by d_o. This gives you the equation \frac{d_o}{f}=\frac{d_o}{d_o}+\frac{d_o}{d_i} d_o/d_o=1 and d_o/d_i=1/M Solve for the remaining d_o.
 

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