- #1

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Can someone give me the step to convert the two equations from general to standard form? If you could, it would be such a great help to me. Thanks

y= x^2 - 2X + 5 and y= -3x^2 + 12x -4

- Thread starter dinahspence
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- #1

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Can someone give me the step to convert the two equations from general to standard form? If you could, it would be such a great help to me. Thanks

y= x^2 - 2X + 5 and y= -3x^2 + 12x -4

- #2

Mark44

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y = A(x - h)

If so, what you need to do is complete the square in your x terms. For example, if your equation was y = -2x

y = -2x

Factor -2 from each of the x terms, getting this:

y = -2(x

Complete the square inside the parentheses, keeping track of what you really added.

y = -2(x

In the step above, it looks like I added 1, but I really added -2, so to keep the right side equal to what it was, I have to balance that by adding + 2.

y = -2(x + 1)

Not sure if this is the form you're looking for, but it is very useful nevertheless. Here we have the equation of a parabola whose vertex is located at (-1, 9).

If this is the form you're looking for, apply the same technique to your problems.

- #3

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thanks!

can anyone help me with the second one?

can anyone help me with the second one?

- #4

symbolipoint

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y= -3x^2 + 12x -4 = -3(x^2 - (-4)x + (4/3))

Now you want to focus most of your attention to completing the square for the polynomial, and then clean the remaining steps.

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