Convert ppm to mg/L - Calculate Grams of A Needed

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SUMMARY

The discussion centers on calculating the amount of stable powder A needed to achieve a concentration of 0.5 ppm of product C in 20 liters of water. Participants confirm that 0.5 ppm equates to 0.5 mg/L, leading to the conclusion that 100 mg of powder A is required to produce the desired concentration of C, given that 10% of A becomes C upon dissolution. The consensus is that the calculation is correct, despite some confusion regarding the wording of the problem.

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Homework Statement


A is a stable powder
B is water
C is the product of the powder being in contact with water.

A is soluble in substance B and for every gram of A 10% is C.

For a concentration of 0.5ppm of C in twenty liters of water how many grams of A do you need?


The Attempt at a Solution


I went on the assumption that ppm=mg/l.
So 0.5ppm=0.5mg/l, and I would need 10mg for the twenty liters
Which means that I would need 100mg of A.

Is this correct?
 
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Cypher49 said:
I would need 100mg of A.

Is this correct?

That would be my answer as well, although I find the wording of the question confusing.
 
Thanks for the confirmation, I'm just replying to say that 100mg was indeed the correct answer.

If you don't mind me asking, how did the wording confuse you?
 
If 0.1g of A reacted with water, what is mass of the product? Again 0.1g? Not impossible, but counterintuitive, at least to me.
 

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