Convert this arithmetic to calculus

[mr magoo]

a = b : this set = this many pieces
a % b = c : this set % this many pieces = this many sets
c * b = a : this many sets * this many pieces = this set
a : c = b : this set % this many sets = this many pieces per set

step 1.) a = 8 pieces
step 2.) a / 4 pieces per set = 2 sets
step 3.) 2 sets * 4 pieces per set = a
step 4.) a : 2 sets = 4 pieces per set

The whole set equals a, step 2 and step 4 use a.
Step 2 uses a and looks to step 3 to find the value of a.

In step 4, parts "8" from step 2 and part "2" from step 3 are blended together, they equal part "4" from step 2.
Step 2 denominator is 4 pieces per set, there is two sets
Step 4 denominator is two sets, there is 4 per pieces per set

e.g.
step 2 = 8/4 = 2
step 4 = 8/2 = 4

Step 4 quotient equals the value of 1 step.
The denominator gives the value of how many steps total.
There is an beginning step to the numerator "8", which equal the quotient "4".
There is an ending step to the numerator "8", which equals the denominator "2".

_______

The above is the arithmetic, but I want to learn calculus to convert it to calculus but I want to know if it's possible to convert this to calculus first.

So my question is is it possible to convert the arithmetic above to calculus? yes or no.

And my second question is, can you do so and post the math for me to look at so when I know calculus I can read your math for reference?

 

[phinds]

So my question is is it possible to convert the arithmetic above to calculus? yes or no.

No, and why would you want to anyway? Arithmetic solves one type of problem and calculus (which of course USES arithmetic) solves a different kind. I think perhaps you have a misinformed idea of just what calculus IS.

 

[mr magoo]

I don't know calculus yet and didn't have any idea if my math could fit into some high math calculation and decided to ask if it fits into calculus, so I asked here.

I guess the math as it is is as technical as it can be explained.
i was just looking for a more technical version of the math is all, but I guess that's the most technical version of it. Thank you for replying.