Converting Cartesian to Polar: Finding the Polar Equation

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SUMMARY

The discussion focuses on converting the Cartesian equation y = 1 + 3x into its polar form. The key equations involved are x² + y² = r², x = Rcos(θ), and y = Rsin(θ). The correct approach is to substitute x and y directly with their polar equivalents rather than squaring the original equation, which leads to unnecessary complexity. The final polar equation can be derived by replacing x and y in the original equation with their polar counterparts.

PREREQUISITES
  • Understanding of Cartesian and polar coordinates
  • Familiarity with trigonometric functions
  • Knowledge of polar equations and their representations
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the conversion process from Cartesian to polar coordinates in detail
  • Learn about the implications of using trigonometric identities in polar equations
  • Explore examples of polar equations derived from various Cartesian forms
  • Investigate the graphical representation of polar equations
USEFUL FOR

Students in mathematics, particularly those studying calculus or analytical geometry, as well as educators and anyone interested in understanding the conversion between Cartesian and polar coordinates.

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Homework Statement


Find a polar equation for the curve represented by the Cartesian equation.

y=1+3x

Homework Equations


x2+y2=r2
x=Rcos(θ)
y=Rsin(θ)

The Attempt at a Solution


(1+3x)2+x2=r2
1+6x+10x2=r2
1+6rcos(θ)+10r2cos2(Θ)=r2
 
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Why are you squaring? This will give you a relation between x^2 and y^2, not x and y, and so not the original equation. Just replace "x" with r cos(\theta) and "y" with r sin(\theta) in the original equations.
 
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HallsofIvy said:
Why are you squaring? This will give you a relation between x^2 and y^2, not x and y, and so not the original equation. Just replace "x" with r cos(\theta) and "y" with r sin(\theta) in the original equations.

Oh thank makes a lot of sense. Thank you.
 

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