Recast a given vector field F in cylindrical coordinates

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Homework Help Overview

The discussion revolves around converting a vector field F from Cartesian to cylindrical coordinates and calculating its curl in both coordinate systems. The original poster attempts to express the vector field F(x,y,z) = xzi in cylindrical coordinates and is also tasked with comparing the curl of F in both systems.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of the Cartesian unit vector i into cylindrical coordinates and its implications for calculating the curl. There are questions about the correctness of the original poster's conversion and the resulting expressions for curl in both coordinate systems.

Discussion Status

Some participants provide guidance on ensuring the unit vector is correctly transformed and suggest that this may resolve discrepancies in the curl calculations. The original poster acknowledges a mistake and indicates they have arrived at an equivalent answer, but there is still a request for verification of specific terms in their results.

Contextual Notes

There is mention of the need to check specific terms in the curl expressions, particularly the e_z component, and the original poster notes that they do not have their homework available for reference during the discussion.

Bestphysics112
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Homework Statement


F(x,y,z) = xzi

Homework Equations


N/A

The Attempt at a Solution


I just said that x = rcos(θ) so F(r,θ,z) = rcos(θ)z. Is this correct? Beaucse I am also asked to find curl of F in Cartesian coordinates and compare to curl of F in cylindrical coordinates. For Curl of F in cylindrical coordinates I obtained rcos(θ)eθ+sin(θ)zez. This doesn't look anything like the curl found in Cartesian coordinates. Where am i going wrong?
 
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The unit vector ## \hat{i} ## also needs to be put in cylindrical coordinates. ## \hat{i}=cos(\theta) \hat{a}_r -sin(\theta) \hat{a}_{\theta} ## if I computed it correctly. Once you do that, you should get agreement when you do the curl operation in cylindrical coordinates. ## \\ ## Editing: Yes, I computed it, and got agreement. I'd be happy to check the answer for you that you get.
 
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Charles Link said:
The unit vector ## \hat{i} ## also needs to be put in cylindrical coordinates. ## \hat{i}=cos(\theta) \hat{a}_r -sin(\theta) \hat{a}_{\theta} ## if I computed it correctly. Once you do that, you should get agreement when you do the curl operation in cylindrical coordinates. ## \\ ## Editing: Yes, I computed it, and got agreement. I'd be happy to check the answer for you that you get.
Hello! Sorry I just saw this reply. As an answer, I got (rcos(θ)sin(θ)er +rcos2(θ)eθ +(2cos(θ)sin(θ)z+ 2sin(θ)cos(θ)z)ez

Is this answer correct?

Edit- Yes! I figured out my mistake and I got an equivalent answer. Thank you for the help Charles
 
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Bestphysics112 said:
Hello! Sorry I just saw this reply. As an answer, I got (rcos(θ)sin(θ)er +rcos2(θ)eθ +(2cos(θ)sin(θ)z+ 2sin(θ)cos(θ)z)ez

Is this answer correct?

Edit- Yes! I figured out my mistake and I got an equivalent answer. Thank you for the help Charles
Please check your ## e_z ## term. The first term gets a minus sign so that the ## e_z ## term is zero. Also what did you get in Cartesian coordinates for the curl? The two should agree and I think they do if the ## e_z ## term is zero.
 
Charles Link said:
Please check your ## e_z ## term. The first term gets a minus sign so that the ## e_z ## term is zero. Also what did you get in Cartesian coordinates for the curl? The two should agree and I think they do if the ## e_z ## term is zero.
I don't have my homework with me, but I forgot to edit my post with the answer I got. The ez terms canceled
 
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