Converting laser fwhm bandwidth in m to hz

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SUMMARY

The discussion focuses on converting the Full Width at Half Maximum (FWHM) bandwidth of a laser from meters to hertz. The user seeks clarification on whether the refractive index should be included in the conversion process, particularly for a ruby laser with a cavity length of 0.1 meters and a refractive index of 1.8. The FWHM gain bandwidth is specified as 2E-9 meters. The user also inquires about the longitudinal mode spacing and the number of lasing modes, emphasizing the need for frequency-based calculations using the formula Df = c * Dlambda / Lambda^2.

PREREQUISITES
  • Understanding of laser physics and FWHM bandwidth
  • Knowledge of the relationship between wavelength and frequency
  • Familiarity with the refractive index and its impact on light propagation
  • Proficiency in applying the formula Df = c * Dlambda / Lambda^2
NEXT STEPS
  • Research the impact of refractive index on laser bandwidth calculations
  • Learn about longitudinal mode spacing in laser cavities
  • Explore the relationship between wavelength and frequency in optical systems
  • Study the implications of FWHM bandwidth on laser performance metrics
USEFUL FOR

Laser physicists, optical engineers, and anyone involved in the design and analysis of laser systems will benefit from this discussion.

melcicero
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hi, pls can someone help me with converting FWHM bandwidth of a laser from metres to hertz
 
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Just from the dimensions
frequency (1/s)= speed (m/s) / wavelength (m)
 
thank you but i didn't think you could directly convert fwhm bandwidth just using that, when i did it i got a bandwidth of region 10E17 Hz -does that seem a bit high from a ruby laser cavity length 0.1m?

If i post the whole question it might help. Also should i include the refractive index of the medium ie c/n=f lambda, if this is the right way to do it?

for the 0.1m cavity, n =1.8, FWHM gain bandwidth is 2E-9m
qu is: what is the longitudinal mode spacing and the number of lasing modes? i could give the spacing in either freq or wavelength but its easier to do i think in freq that's why i wanted to convert. many thanks if you can help.
 
you can use the following formula

Df=c*Dlambda/Lambda^2
 

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