Converting mks energy density to cgs

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SUMMARY

The discussion focuses on converting the energy density of electric and magnetic fields from the SI system to the Gaussian (cgs) system. The energy density is initially expressed as u = \frac {\epsilon_{0} E^{2}}{2} + \frac{B^{2}}{2 \mu_{0}}. Key insights include the elimination of \epsilon_{0} and \mu_{0} in the cgs system, leading to a simplified expression U_{tot} = E^{2} + B^{2}. Participants recommend consulting JD Jackson's "Electrodynamics" and relevant Wikipedia articles for deeper understanding and clarification of the differences between the SI and cgs systems, particularly regarding the constants and their implications.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically energy density concepts.
  • Familiarity with SI and Gaussian (cgs) unit systems.
  • Basic knowledge of Coulomb's law and its implications in different unit systems.
  • Experience with mathematical manipulation of physical equations.
NEXT STEPS
  • Study the conversion of electromagnetic equations from SI to Gaussian units.
  • Learn about the implications of 4\pi factors in cgs units.
  • Examine JD Jackson's "Electrodynamics" for detailed explanations on energy density.
  • Review the Wikipedia page on the electromagnetic stress-energy tensor for additional context.
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism and unit conversions, as well as educators seeking to clarify these concepts for their students.

syang9
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Homework Statement



In the SI system, the energy density of the electric and magnetic fields is:

<br /> u = \frac {\epsilon_{0} E^{2}}{2} + \frac{B^{2}}{2 \mu_{0}}<br />

From the equation above, derive an exact expression for the energy density U in the Gaussian system of units.


The Attempt at a Solution



Obviously the energy densities must be proportional to the squares of the intensities. So, I can start with

U_{tot} = E^{2} + B^{2}

I know that cgs eliminates the need for epsilon and mu, but I haven't a clue as to how to start from that one equation. Previously in the assignment, my instructor mentions that in Coulomb's law, \epsilon_{0} has been eliminated by redefining the electric charge in the Coulomb law (\frac{q_{1} q_{2}}{4 \pi \epsilon_{0}} \rightarrow q_{1} q_{2}) and \mu_{0} has been eliminated by using the speed of light: \mu_{0} \rightarrow \frac{1}{c^{2} \epsilon_{0}}.

However I haven't a clue as to how to proceed with this information. Any hints would be great! Thanks in advance.

Stephen
 
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There's an epsilon and a mu in the cgs system as well. There's something linked with #-s and 4\pi-s that differs. On a second thought, since i haven't used cgs since college, go and check the 3-rd and 2-nd editions of JD Jackson's electrodynamics book to see everything exactly.
 
Last edited:
syang9 said:

Homework Statement



In the SI system, the energy density of the electric and magnetic fields is:

<br /> u = \frac {\Epsilon_{0} E^{2}}{2} + \frac{B^{2}}{2 \mu_{0}}<br />

From the equation above, derive an exact expression for the energy density U in the Gaussian system of units. Stephen
Hopefully you found this one already:

http://en.wikipedia.org/wiki/Electromagnetic_stress-energy_tensor

If \frac {1}{4 \pi \epsilon_{0}} = 1, then \epsilon_{0} = \frac {1}{4 \pi}, and likewise for magnetic field.

Although, often epsilon is not what it seems in cgs. It really depends on whether you are looking at emu or esu. I recommend this document, which gives you a little taste of the complications of calling 4 \pi = 1, or \epsilon_{0} = 1, despite it's readability difficulties:

http://www.scribd.com/doc/8520766/Cgs-Electricity-and-Magnetism
 

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