Converting Planck's Constant for Energy Unit Matching

  • Thread starter Thread starter Erwin Schrodinger
  • Start date Start date
  • Tags Tags
    Constant
Click For Summary
SUMMARY

The discussion centers on the conversion of Planck's constant for energy unit matching in the equation E = hf. Users can either convert energy from electronvolts (eV) to Joules or use Planck's constant in eV-seconds. The correct value for Planck's constant in eV-s is approximately 4.14 x 10^-15 eV-s. The equation E(eV) = 1.24/λ(μm) is also mentioned as a useful approximation for energy calculations.

PREREQUISITES
  • Understanding of the equation E = hf
  • Familiarity with energy units: electronvolts (eV) and Joules (J)
  • Basic knowledge of Planck's constant and its significance in quantum mechanics
  • Awareness of wavelength-energy relationships in photon energy calculations
NEXT STEPS
  • Research the conversion methods between eV and Joules
  • Learn about the significance of Planck's constant in quantum mechanics
  • Explore the application of the equation E(eV) = 1.24/λ(μm) in practical scenarios
  • Investigate the implications of using different units in physics equations
USEFUL FOR

Physics students, educators, and professionals in fields related to quantum mechanics and photonics will benefit from this discussion, particularly those working with energy calculations involving photons.

Erwin Schrodinger
Messages
24
Reaction score
0
When using the equation E = hf to find the energy of a photon, do I convert the energy and Planck's constant so they contain the same energy unit? So if I use eV for energy, I convert Planck's constant to eVs? If so, then Planck's constant would be about 4.14(10^-15)eVs? Thanks for the help in advance.
 
Physics news on Phys.org
You need to use the same units on both sides of any equation.

What you're doing is perfectly OK. You can either convert the energy from eV to standard units (Joules) and then use Planck's constant in J-s. Or just use Plank's constant in eV-s, as you did.
 
Your conversion is perfectly fine, and your new units for the Planck constant would be Joules Coulomb per second or eV/s. For convenience, the approximation

E(eV) = \frac{1.24}{\lambda (\mu m)}

is often used as well.
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 25 ·
Replies
25
Views
5K
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
0
Views
1K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K