- #1

Hapablap

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***Edit: Nevermind, I realize where I went wrong!**

## Homework Statement

The following graph shows the kinetic energy of the most energetic photoelectrons as a function of the frequency of light falling on the cathode in a photoelectric cell.

http://img208.imageshack.us/img208/3421/fwby.jpg

Use the graph to determine the value of Planck's constant.

## Homework Equations

E = hf

h = E/f

## The Attempt at a Solution

I'll choose the point where E = 3.0 eV and f = 10.0 Hz for my calculation.

First I'll convert eV to Joules:

3.0 eV x (1.60 x 10^-19 J / 1 eV) = 4.8 x 10^-19 J

Now the calculation:

h = E/f

h = (4.8 x 10^-19 J) / (10.0 x 10^14 Hz)

h = 4.8 x 10^-34 J(s)

We already know that the value of Planck's constant is 6.63 x 10^-34 J(s), so my answer is off.

Any suggestions?

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