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- Thread starter bglb212
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Problem solved!

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- #2

Mark44

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Your relevant equations show the converstion from spherical to Cartesian coordinates. Do you know the conversions going in the other direction?

One trick that will be helpful is to multiply both sides by rho. This potentially adds a point (rho = 0) that might not be a solution of your original equation, so you should check whether this is already a solution of your equation.

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Mark44

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vela

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- #7

Mark44

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You're missing a factor of cos(phi) in the numerator on the right side.

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vela

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Try bringing the (1+cos^2(phi)) to the other side.

- #10

Mark44

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OK. I didn't catch what you were doing.I dont think so, because doesnt pcos(phi)=z?

Don't you mean (1 - cos^2(phi))?vela said:Try bringing the (1+cos^2(phi)) to the other side.

- #11

Mark44

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It's probably helpful not to change the rho^2 on the left side just yet.bglb212 said:x^2+y^2+z^2=z/(1-cos(phi)^2

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- #13

Mark44

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You have rho^2 = z/(1 - cos^2(phi))

What do you get when you multiply both sides by 1 - cos^2(phi)?

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- #15

vela

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Yes, I did. Thanks for catching that.Don't you mean (1 - cos^2(phi))?

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Mark44

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That's a very nice thing to say! Thank you!got it, I like you mark. you're helpful. may your children be plentiful and live long

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- #18

Mark44

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csc(x) = 1/sin(x), cot(x) = cos(x)/sin(x)

Are those the ones you mean?

Are those the ones you mean?

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Evo

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