Converting Velocity from mph to ft/s: How to Rewrite a Constant Formula

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SUMMARY

The discussion focuses on converting the velocity formula V = 5.47√h from miles per hour (mph) to feet per second (ft/s). The correct conversion factor is established as 1 mph = 1.467 ft/s, leading to the conclusion that the new constant for the formula should be 8.02 ft/(s ft^(1/2)). Participants emphasize the importance of unit conversion in the constant to ensure the formula outputs velocity in the desired units.

PREREQUISITES
  • Understanding of unit conversion, specifically between mph and ft/s.
  • Familiarity with the formula V = 5.47√h and its components.
  • Basic knowledge of dimensional analysis and how to manipulate units.
  • Experience with mathematical constants and their application in formulas.
NEXT STEPS
  • Research the Grid Method for unit conversion in mathematical formulas.
  • Learn about dimensional analysis to ensure unit consistency in equations.
  • Explore the implications of using different units in physics and engineering calculations.
  • Study the derivation of conversion factors between various speed units, such as mph to ft/s.
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Mathematicians, physics students, engineers, and anyone involved in converting units in formulas for velocity calculations.

Ryuk1990
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Ok, here is a certain formula and I have to change it.

V = 5.47\sqrt{h}

V is velocity in mph while h is distance in ft.

I need to determine a new constant so that V is in feet per second. How do I go about doing that? Do I just convert V first and then take the constant and multiply it by the numbers that I needed to convert to ft/s?

By the way, h stays the same as just ft.
 
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If 1 mph is 1.67 ft/s (recheck this for me)

How much ft/s is V mph?

EDIT: As Char. Limit says, 1mph is 1.467 ft/s

I forgot a 4 it seems.
 
Last edited:
Err...

1 mph is not 1.67 ft/s.

1 mph is 1.467 ft/s
 
There are 5280 ft/mi. There are 60 sec per minute and 60 minutes per hour and so 3600 seconds per hour.

1 mi/hr= (1 mi/hr)(5280 ft/mi)/(60 sec/hr)= 5280/60 (mi/hr)(ft/mi)(hr/sec= 1.47 ft/sec.
 
And there are 1000 metres / kilometre

I dunno... metric units just seem simpler...
 
Yeah I know how to convert but I'm asking how do I change the constant 5.47 in the formula to accommodate V in ft/sec? Do I just multiply 5.47 by the numbers that I multiplied into V to convert it?
 
I believe you would just multiply the equation the same way HallsofIvy has done; it's called the Grid Method.
 
Ryuk1990 said:
Ok, here is a certain formula and I have to change it.

V = 5.47\sqrt{h}

V is velocity in mph while h is distance in ft.

I need to determine a new constant so that V is in feet per second. How do I go about doing that? Do I just convert V first and then take the constant and multiply it by the numbers that I needed to convert to ft/s?

By the way, h stays the same as just ft.
Just put the units in explicitly:

v=5.47 \frac{\mbox{miles}}{\mbox{hr ft}^{1/2}}\sqrt{h}

and convert the units on the constant like you normally do.
 
vela said:
Just put the units in explicitly:

v=5.47 \frac{\mbox{miles}}{\mbox{hr ft}^{1/2}}\sqrt{h}

and convert the units on the constant like you normally do.

I have no idea how you got that unit for the constant.

I also don't know what you mean by converting the units on the constant like you normally would. Convert the units on the constant into what?
 
  • #10
The units of \sqrt{h}, if h is in feet, is ft1/2, which cancels with the ft1/2 in the denominator of the units of the constant. The units of v is mph, so the what's left over after the ft1/2 cancels must be miles/hr.

If you want the formula to give an answer in ft/s, the constant needs to have units of ft/(s ft1/2).
 
  • #11
I got 8.02 as the new constant. Is that right?
 

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