Converting Voltage to Pressure: A Simple Guide for Engineering Students

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SUMMARY

This discussion focuses on converting voltage readings (1 to 5 volts) into pressure measurements (0 to 200 bars) using linear transformation. The formula used is P = mV + b, where P represents pressure and V represents voltage. By substituting known values into the equations, users can derive the slope (m) and y-intercept (b) necessary for the transformation. A more efficient method involves calculating the slope directly as m = delta P / delta V, yielding a slope of 50 for this specific case.

PREREQUISITES
  • Understanding of linear equations and the formula y = mx + b
  • Basic knowledge of pressure measurement units (bars)
  • Familiarity with voltage measurement units (volts)
  • Ability to solve simultaneous equations
NEXT STEPS
  • Learn how to derive linear equations from real-world data
  • Explore the concept of slope and intercept in linear transformations
  • Study applications of linear equations in engineering contexts
  • Investigate alternative methods for data transformation in engineering
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Aerospace engineering students, electrical engineers, and anyone involved in data analysis or sensor calibration in engineering applications.

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Hey guys, I am a sophomore college student studying Aerospace Engineering and I am doing an experiment, and i ran into a little math problem that i can't seem to visualize properly.

I have a y-axis where which is a measure of pressure (from 0~200 bars), but expressed in voltages (1 to 5 volts).

In order to properly analyze the results, i have to linearly transform the 1~5 volt scale to a 0~200 bar scale.

I know it involves simple pre-calculus (with the y=mx+b) stuff but I just can't remember whatever I did in high school.

Can anyone help me out here?

Thanks in advance
 
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The formula y = mx + b you gave is for a straight line, i.e. a linear dependence. For this application, let me rename y to P (for pressure) and x to V (for voltage): P = m V + b.
What you can do now, is simply plug in two points that you want to correspond. For example, if 1 volt corresponds to 0 bar, set V = 1, P = 0 to get
0 = m 1 + b = m + b
Take another point, for example to let 5 volts correspond to 500 bar, set V = 5, P = 500:
500 = 5m + b.

This gives you two equations from which you can solve m and b (for example, the first one gives you b = -m, plugging that into the second one produces 500 = 5m - m = 4m and then you can find m).

(Note that there are faster ways, such as calculating m = delta P / delta V = (200 - 0) / (5 - 1) = 200 / 4 = 50 and then plugging in one point, but this one is more general).
 

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