Convolution area property derivation

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The discussion focuses on deriving the area property of convolution, specifically showing that the area under the convolution y(t) of two functions x(t) and h(t) equals the product of their individual areas. A user shares a derivation that omits a crucial step regarding the separation of integrals. The main question revolves around the process of exchanging the order of integration in the convolution definition. Clarification is sought on the mathematical justification for this step in the derivation. Understanding this concept is essential for grasping the area property in convolution.
mafra
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Homework Statement


Let y(t) be the convolution of x(t) with h(t), show that the area under y(t) is the product of the areas under x(t) and h(t)

Homework Equations


Convolution definition

The Attempt at a Solution


I found a derivation but it skips a step, uploaded it here:
htt p://i50.tiny pic.com/s15dus.jpg
 
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What's the step that you were wondering about?

s15dus.jpg
 
I don't get how it is possible to separate the integrals in "exchanging the order of integration"
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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