Convolution Properties and Fourier Transform

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The discussion focuses on two assertions regarding convolution and Fourier transforms. The first assertion states that if the convolution of two functions results in one of the original functions, the second function must be an impulse, which is confirmed as true. The second assertion suggests that if the convolution of two functions is identically zero, then at least one of the functions must also be identically zero; this is debated, with examples provided that show two non-zero functions can still convolve to zero. The importance of understanding the properties of convolution and their implications in Fourier transforms is emphasized. Overall, the conversation highlights key concepts in signal processing and mathematical analysis.
Pewgs
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Homework Statement



Determine whether the assertions are true or false, explain.
(a) If (f * g)(t) = f(t), then g(t) must be an impulse, d(t).
(b) If the convolution of two functions f1(t) and f2(t) is identically zero,
(f1 * f2)(t) = 0
then either f1(t) or f2(t) is identically zero, or both are identically zero.

Homework Equations



Fourier Transform implies that Xf1(jw)*Xf2(jw)=transform on the convolution.

The Attempt at a Solution


a) If Xf1(jw)*Xf2(jw)=Xf1(jw) then Xf2(jw) must be equal to 1, which is the same as d(t).

Not sure about b...
 
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Welcome to PF, Pewgs! :smile:

Your (a) looks good!

For (b) you should perhaps consider 2 transforms that multiply to zero, but are not zero themselves.
For instance a Heaviside function and its mirror.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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