Fourier Transform: Determining Constant in Convolution

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SUMMARY

The discussion centers on applying the convolution theorem to determine the Fourier series of the product of two functions, h(t) = f(t)g(t), where both f(t) and g(t) possess discrete Fourier series. The convolution theorem transforms the product into a convolution in the frequency domain, represented as ∑ωnf(a-ωn)g(ωn). A key point of confusion is the determination of the constant 'a' in this context, which is essential for accurately computing the Fourier transform and convolution. The discussion highlights the necessity of understanding the role of 'a' as the argument of h in both the Fourier series and the Fourier transform.

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  • Understanding of Fourier series and transforms
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  • Knowledge of discrete Fourier transforms
  • Basic concepts of frequency domain analysis
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I have an exercise with a function of the form:

h(t) = f(t)g(t)

and f(t) and g(t) both have discrete Fourier series, which implies that h does too. I want to find the Fourier series of h, so my teacher said I should apply the convolution theorem which would turn the product above into a convolution in the frequency domain.

ωnf(a-ωn)g(ωn)

But the problem for me is that it seems arbitrary for me what the constant a should be? How is that determined?

The problem also arises in the case where I have a product as above but I want to find the Fourier transform (i.e. now not series but proper integral transform).
The FT will be a convolution but what determines the constant in the convolution?
 
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I suppose you have \hat{h}(a)=\sum_{\omega_n}\hat{f}(a-\omega_n)\hat{g}(\omega_n),

so that a is the argument of h.
 

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