How to Correctly Convolve x[n] with a Unit Step Function?

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To convolve x[n] with the unit step function h[n] = u[n], the correct approach involves using the convolution definition y[n] = ∑ (k = -∞ to +∞) x[k] h[n-k]. Initial attempts to flip and shift h[n] resulted in all zeros, indicating a misunderstanding of the convolution process. The correct convolution yields a non-zero sequence based on the values of x[n], represented as a sum of shifted and scaled impulses. The graphical method can aid in visualizing this process, demonstrating how to align and sum the contributions from x[n]. Understanding these principles is crucial for accurately performing convolution with unit step functions.
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Homework Statement


Find convolution of x[n] (graph in attachment) and h[n] where h[n] = u[n]
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Homework Equations

The Attempt at a Solution


- flipped the h[n] to have h[-n]
- moved to the left once (h[-1-n]) to align
- multiplied h and x and it gives me all zeros

Is this correct or I'm missing something?
 
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I don't know about your graphical algorithm but if you use the definition

y[n] = x[n]*h[n] = ∑ (k = -∞ to +∞) x[k] h[n-k]

then I get a non-zero sequence of numbers:

a+0.5, b+0.5, c+0.5, c+0.5, d+0.5, d+0.5, d+ 0.5, ...

wher a, b , c, and d are positive integers for you to find.
 
Just think x(n) as sum of shifted and scaled impulses . Since you know the convolution of a signal h(n) with shifted impulse will be shifted h(n) and then you add them .
 

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