Convolutions of Lebesgue integrable functions

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SUMMARY

The discussion centers on the properties of convolutions of Lebesgue integrable functions, specifically within the context of the convolution defined as \( f*g=\int_R f(x-y)g(y) dy \) for functions \( f, g \in L^1(R) \). It is established that the convolution \( f*g \) is also integrable, and the proof involves demonstrating that \( ||f*g||_1=\int_R\int_R f(x-y)g(y) dy dx \) holds true. The confusion arises regarding the interchange of integration variables and the relationship between Lebesgue and Riemann integrals, highlighting a common misunderstanding in integral calculus.

PREREQUISITES
  • Understanding of Lebesgue integration and its properties
  • Familiarity with the concept of convolutions in functional analysis
  • Knowledge of \( L^1(R) \) spaces and integrable functions
  • Basic principles of measure theory, particularly Lebesgue measure
NEXT STEPS
  • Study the properties of convolutions in \( L^p \) spaces
  • Learn about Fubini's Theorem and its application in switching the order of integration
  • Explore the differences between Lebesgue and Riemann integrals
  • Investigate the implications of integrability conditions on convolutions
USEFUL FOR

Mathematicians, students of real analysis, and anyone studying functional analysis or measure theory will benefit from this discussion, particularly those focusing on integrable functions and convolutions.

redbowlover
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Hello,

Looking through Torchinksy's Real Variables text and I'm infinitely confused about convolutions.

For two integrable functions f, g \in \ L^1(R) we define the convolution f*g=\int_R f(x-y)g(y) dy , \forall x\in R.

Then, apparently, f*g is also integrable. But I'm not sure how to prove this. The text says, for now suppose f, g and the integrand are nonnegative. Then ||f*g||_1=\int_R\int_R f(x-y)g(y) dydx.

But why is this true? Clearly ||f*g||_1=\int_R\int_R f(x-y)g(y) dydm, where m is the Lebesgue measure. But what allows you to switch to dx? Maybe this speaks to my greater misunderstanding of integrals. Sigh...If anyone could explain this to me I'd be very grateful.

I thought in general you could only switch from Lebesgue integration to Riemann integration when you knew the thing was Riemann integrable.
 
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He writes $\int_R f(x) dx$ to mean the Lebesgue integral.
 

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