Calculating Cooling Load for Water Tank on Building Roof?

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SUMMARY

This discussion focuses on calculating the cooling load for a 5 cubic meter water tank installed on a building roof, requiring cooling from 55°C to 25°C. The user employs the formula q = m * c * delta T to determine the heat transfer rate, resulting in a calculation of 10.75 TR (Tons of Refrigeration). The user seeks clarification on the accuracy of this calculation and guidance on selecting an appropriate cooling coil for the tank.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat transfer.
  • Familiarity with the formula q = m * c * delta T for calculating heat transfer.
  • Knowledge of refrigeration concepts, including Tons of Refrigeration (TR).
  • Experience with insulation techniques to minimize solar heat gain.
NEXT STEPS
  • Research the specific heat capacity of water and its implications in cooling load calculations.
  • Learn about the selection criteria for cooling coils in HVAC systems.
  • Investigate insulation materials and their effectiveness in reducing heat gain for water tanks.
  • Explore the relationship between cooling load calculations and the sizing of heat pumps.
USEFUL FOR

Engineers, HVAC professionals, and anyone involved in thermal management and cooling system design for water tanks or similar applications.

gaber2611
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Hello everybody,

I have been here before, with different username and cause i didn't log into long time ago, the username doesn't work for m now, so here i am with the new user.

Just as a respect for the forum rules, to not post a topic once i register.

i am doing cooling load calculations, for cooling a 5 cubic meters volume water tank, drains 1000l/day, exposed to sun, installed on building roof, to cool water from 55 to 25 celcuis degrees, working hours of the coil is 12hrs during the day.

i am thinking to insulate the tank, so solar heat gain won't be taken into account for cooling load, and it will be only the heat transfer between the water and fereon cooling coil, which can be calculated using the formula:

q= m*c*delta t

i calculated it, and the result didn't make sense to me, so i need your help with the calculation result.
will appreciate your reply, as i am in urgent need to do that work.
Thanks in advance.
 
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What you're calculating is the heat transfer rate of the water to change the temperature from 55 to 25 degrees C. What doesn't it make sense? It'd be helpful if you gave us the calculation that you did. If you wanted to incorporate other factors it will require other relations.
 
Thanks vadar for your reply,

here is my calulations,which doesn't make sense to me:q= m * c * delta T
= (1*5)grams * 4.18 j/g.C * 30 C.
= 627 J (watt/sec.) , = 627*60 w/hr ,= 37.62 kw/hr.
1 TR = 3.5 kw, then q= 10.75 TR.

does this make sense to you?, when you buy a heat pump with that capacity?,isn't it too big?, or i did something wrong?,if wrong, what are the relations or procedures to select the right cooling coil for that water tank?
 
anyone to help?
 

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