Corollary 3.1.3 - Berrick and Keating - Noetherian Modules

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The discussion centers on the proof of Corollary 3.1.3 from "An Introduction to Rings and Modules with K-theory in View" by A.J. Berrick and M.E. Keating, specifically regarding its relationship to Proposition 3.1.2. Users seek clarification on the proof, which is not provided in the text, and discuss the generation of direct sums of modules. The participants confirm that if $\{m_1,\dots,m_k\}$ generates module $M$ and $\{n_1,\dots,n_r\}$ generates module $N$, then the set $\{(m_1,0),\dots,(m_k,0),(0,n_1),\dots,(0,n_r)\}$ generates the direct sum $M \oplus N$. Additionally, they explore the short exact sequence associated with direct sums.

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I am reading the book "An Introduction to Rings and Modules with K-theory in View" by A.J. Berrick and M.E. Keating ... ...

I am currently focused on Chapter 3; Noetherian Rings and Polynomial Rings.

I need help with the proof of Corollary 3.1.3.

The statement of Corollary 3.1.3 reads as follows (page 110):https://www.physicsforums.com/attachments/4875Now, Berrick and Keating give no proof of this Corollary: presumably they think the proof is simple and obvious. Maybe it is ... but I need help in formulating a formal and rigorous proof ... can someone please help ...Because we are dealing with a Corollary to Proposition 3.1.2 readers of this post need the text of that Proposition. Proposition 3.1.2 and its proof are as follows:https://www.physicsforums.com/attachments/4876
https://www.physicsforums.com/attachments/4877Hope someone can help with the proof of Corollary 3.1.3 ... ...

Peter
 
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Suppose $\{m_1,\dots,m_k\}$ generate $M$, and $\{n_1,\dots,n_r\}$ generate $N$.

Then $\{(m_1,0),\dots,(m_k,0),(0,n_1),\dots,(0,n_r)\}$ generate $M \oplus N$.

For example, $\{(1,0),(0,1)\}$ generates $\Bbb Z \oplus \Bbb Z$.
 
Deveno said:
Suppose $\{m_1,\dots,m_k\}$ generate $M$, and $\{n_1,\dots,n_r\}$ generate $N$.

Then $\{(m_1,0),\dots,(m_k,0),(0,n_1),\dots,(0,n_r)\}$ generate $M \oplus N$.

For example, $\{(1,0),(0,1)\}$ generates $\Bbb Z \oplus \Bbb Z$.
Oh OK ... thanks Deveno ... clear now ... appreciate your help ...

BUT ... clear as it is ... it does not seem to be a Corollary of Proposition 3.1.2 ... how does it depend on Proposition 3.1.2

Can you help with the second statement of the Corollary?

Peter
 
Last edited:
For any direct sum $M \oplus N$ we clearly have the short exact sequence:

$0 \to M \to M \oplus N \to N \to 0$,

where $\alpha: M \to M \oplus N$ is given by $\alpha(m) = (m,0_N)$

and $\beta: M\oplus N \to N$ is given by $\beta(m,n) = n$.
 

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