Correct differentiation identity? (tensors, vectors)

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SUMMARY

The differentiation identity for a vector and a second-order tensor is confirmed as correct: \nabla\cdot(\vec{v}\cdot\boldsymbol{A}) = \nabla\vec{v}:\boldsymbol{A} + \vec{v}\cdot\nabla\cdot\boldsymbol{A}. This identity utilizes the double dot product and is essential for understanding tensor calculus in physics and engineering. The discussion emphasizes the need for clarity in notation and provides a reference to the Wikipedia page on vector calculus for further details.

PREREQUISITES
  • Understanding of vector calculus
  • Familiarity with tensor notation
  • Knowledge of the double dot product
  • Basic principles of differentiation in multi-variable calculus
NEXT STEPS
  • Study the Wikipedia page on vector calculus for foundational concepts
  • Learn about the properties of second-order tensors
  • Explore applications of differentiation identities in physics
  • Investigate advanced tensor calculus techniques
USEFUL FOR

This discussion is beneficial for students and professionals in mathematics, physics, and engineering, particularly those working with tensor calculus and vector analysis.

Waldheri
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Hello,

I'm working on some problems and I want to pose the following, though I am not completely sure it is correct. Can somebody point me to some sources on this? I have tried googling myself, but I only found differentiation identities with either just vectors and scalars on the on hand, or dot products between tensors on the other hand.

Note: \boldsymbol{A} denotes a second-order tensor, \vec{v} denotes a vector and : the double dot product.

\nabla\cdot(\vec{v}\cdot\boldsymbol{A}) = \nabla\vec{v}:\boldsymbol{A} + \vec{v}\cdot\nabla\cdot\boldsymbol{A}

So in other words: is the above identity correct?
 
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