Corrector for the Ehrenfets equation

  • Thread starter Thread starter carllacan
  • Start date Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
carllacan
Messages
272
Reaction score
3

Homework Statement



The potential V(x) in the equation
[itex]m\frac{d^2}{dt^2}=-\left \langle \frac{d\hat{V}}{dx} \right \rangle[/itex]
changes very slowly for the typical wavelength wavefunction. Calculate the lowest corrector for the classical equation of motion.

Homework Equations


The Ehrenfest Theorem
[itex]m\frac{d^2}{dt^2}=-\left \langle \frac{d\hat{V}}{dx} \right \rangle[/itex]

The Attempt at a Solution


I don't understand the question. I can't find in any book a mention of a corrector for the Ehrenfest equation. And what does it mean with the wavelentgh of the wavefunction?

Thank you for your time.
 
Physics news on Phys.org
Funny, your only relevant equation is also a given in this exercise. My (very old ) QM book has ## {d\over dt}<{\bf p}> = -\int \Psi^* (\nabla V)\Psi\, d\tau = -<\nabla V> = <{\bf F}> ##as Ehrenfest's theorem; with the comment: "this is simply Newton's law, but now for expectation values".

Must say my book is easier to understand for me than your rendering of he exercise: ## m\frac{d^2}{dt^2}\,## looks like an operator to me, not an expectation value like ## -\left \langle \frac{d\hat{V}}{dx} \right \rangle\,##.

So I am on your side in "not understanding the question". I need some reassurance this really is exactly how the exercise was formulated...

This link, by prof. Fitzpatrick, Texas university Austin, sides with Eugen Merzbacher. It makes me think a <x> fell by the wayside somewhere...

Wavelength of the wave function generally has a ##\hbar## in it somewhere, making the wavelength real small compared to change in V.