Cosine for synchronous demodulation

Click For Summary
SUMMARY

The discussion focuses on the process of synchronous demodulation of the signal x(t) defined by the equation x(t) = xc(t)*(1+m*xm(t)), where xc(t) = cos(2pi*fc*t) with a carrier frequency fc of 2000 Hz and xm(t) = cos(2pi*fm*t) with a modulation frequency fm of 200 Hz. The modulation index m is set at 0.8. Participants emphasize the necessity of multiplying x(t) by the carrier function xc(t) to recover the original modulating signal xm(t). The confusion around the correct approach highlights the importance of understanding the principles of synchronous demodulation.

PREREQUISITES
  • Understanding of synchronous demodulation principles
  • Familiarity with trigonometric functions and their applications in signal processing
  • Knowledge of modulation techniques, specifically amplitude modulation
  • Basic grasp of signal recovery methods in communication systems
NEXT STEPS
  • Study the mathematical foundations of synchronous demodulation
  • Learn about the role of carrier signals in communication systems
  • Explore the concept of modulation index and its impact on signal processing
  • Investigate practical applications of synchronous demodulation in real-world communication systems
USEFUL FOR

Students and professionals in electrical engineering, particularly those focusing on communication systems, signal processing, and modulation techniques.

ƒ(x)
Messages
327
Reaction score
0

Homework Statement



Synchronous demodulate x(t).

Homework Equations



xc(t) = cos(2pi*fc*t), fc is the carrier frequency
xm(t) = cos(2pi*fm*t), fm is the modulation frequency

x(t) = xc(t)*(1+m*xm(t)), m is the modulation index
m = .8
fc = 2000 hz
fm = 200 hz

The Attempt at a Solution



I really don't even know where to start. I know synchronous demodulation means I multiply x(t) by a function, but how do I come up with that function? I realize that I could divide x(t) by (1+m*xm(t)), but that doesn't seem to be what the problem is asking.
 
Physics news on Phys.org
ƒ(x) said:
xc(t) = cos(2pi*fc*t), fc is the carrier frequency
xm(t) = cos(2pi*fm*t), fm is the modulation frequency

x(t) = xc(t)*(1+m*xm(t)), m is the modulation index
m = .8
fc = 2000 hz
fm = 200 hz

The Attempt at a Solution



I really don't even know where to start. I know synchronous demodulation means I multiply x(t) by a function, but how do I come up with that function? I realize that I could divide x(t) by (1+m*xm(t)), but that doesn't seem to be what the problem is asking.
No, that would involve the receiver being able to predict the modulation perfectly, so there would be little point in sending it in the first place.

I don't know where to start, either. But isn't synchronous something about multiplying by the carrier? So why not try multiplying x(t) by xc(t) and see what you can get from that? The whole idea is to recover xm(t), presumably?
 
NascentOxygen said:
No, that would involve the receiver being able to predict the modulation perfectly, so there would be little point in sending it in the first place.

I don't know where to start, either. But isn't synchronous something about multiplying by the carrier? So why not try multiplying x(t) by xc(t) and see what you can get from that? The whole idea is to recover xm(t), presumably?

I think I'm supposed to do x(t) * xc(t) and then the next step is to use a step function of sorts. The point is to recover xc(t) since that's the original signal.

Edit: My mistake, I was misreading the problem. You're correct. I'm supposed to recover xm(t).
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
Replies
9
Views
3K
Replies
5
Views
2K
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
61
Views
15K