Could Dark Mass Be a Possible Explanation for Missing Particles in the Universe?

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SUMMARY

The discussion centers on the concept of "dark mass" as a potential explanation for the missing mass in the universe, contrasting it with the traditional notion of dark matter. Participants explore the idea that spacetime itself may store mass, referencing concepts from general relativity (GR) and the Higgs boson. Key points include the notion that spacetime is "springy," which could imply stored energy manifesting as missing mass at low accelerations. The conversation also touches on the stability of the Higgs boson and its implications for dark matter hypotheses, emphasizing the speculative nature of current theories.

PREREQUISITES
  • Understanding of general relativity (GR) and its implications for spacetime curvature
  • Familiarity with the Higgs boson and its role in particle physics
  • Knowledge of baryon acoustic oscillations and their significance in cosmology
  • Basic principles of scalar fields and their interactions with matter
NEXT STEPS
  • Research the implications of spacetime curvature on mass-energy equivalence in general relativity
  • Explore the stability and properties of the Higgs boson in particle physics
  • Investigate baryon acoustic oscillations and their role in understanding dark matter
  • Examine current theories and models of dark matter, including alternative hypotheses
USEFUL FOR

Physicists, cosmologists, and researchers interested in theoretical physics, particularly those exploring the nature of dark matter and the fundamental properties of spacetime.

  • #61
Driftwood1 said:
...and yet photons exert pressure (photoelectric effect, solar sails)

interesting
Yes, because photons also have momentum equal to their energy. In relativistic terms, the total energy of a particle is:

E^2 = p^2 c^2 + m^2 c^4

Notice that in the case of zero momentum (p is the momentum of the particle), this equation reduces to the more familiar:

E = mc^2[/itex]<br /> <br /> This is actually just a special case, as the energy is only equal to the mass in the non-moving case. With photons, which have zero mass, the energy reduces to:<br /> <br /> E = p c<br /> <br /> Since photons have momentum, they can impart that momentum on other objects when they are absorbed or bounce off of them. And so a bunch of photons hitting an object together exert pressure.
 
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  • #62
Weeble said:
I'm new to blogs so this is my first post. I'm also no physicist by any stretch of the imagination but I love science. My question is this, if light is slowed when it moves through a medium which has mass, and it seems the belief is that dark matter has mass and is everywhere, isn't light actually slowed by dark matter? It seems to me that if this is true then light should actually be faster than what we know it to be. If, for example, there was a true "vacuum" devoid of any dark matter would light travel faster or is the speed of light already based on a true vacuum with no dark matter in the equation?
Light isn't slowed by mass. It's slowed by electromagnetic interactions. So light is basically unaffected by dark matter, which has no charge with which light can interact.
 
  • #63
Chalnoth said:
E = p c


... p=\frac{h}{c}f

Momentum is dependent on the frequency (or wavelength) of the photon

(just trying out the cool symbols etc availiable on this chat site)
 
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  • #64
"Mass is the non-kinetic energy of an object." originally posted by chalonth

what do you mean by this i thought mass was the amount of matter inside an object
 
  • #65
inflector said:
I'm interested to see Ich's response but in thinking about it, it's obvious that spacetime moves back to straight/flat if you take the matter away, so in that sense, it wants to be straight/flat.

i agree but then what would happen i too big of a mass made a rip in space time and then that mass dissapeared?(theoretically of course)
 
  • #66
dman124 said:
"Mass is the non-kinetic energy of an object." originally posted by chalonth

what do you mean by this i thought mass was the amount of matter inside an object
Nope. If you have a block of wood, and raise its temperature, its mass increases. It just so happens that for reasonable temperatures, that mass increase is almost completely negligible. But for quantum systems the mass difference due to similar effects can be significant.

For example, if you compare the masses of a proton and a neutron separately, and then to a deuterium ion (which is a bound state of a proton and a neutron), you find that the deuterium ion has about 0.1% less mass. This is an indication that the deuterium ion is a lower-energy configuration than a separate neutron and proton.

Even more striking, however, is what happens inside the protons and neutrons. The masses of the individual quarks that make up the proton and neutron are only around 1-2% of the total mass. The rest of the mass comes from the binding energy of the quarks.
 
  • #67
dman124 said:
i agree but then what would happen i too big of a mass made a rip in space time and then that mass dissapeared?(theoretically of course)
So far as we are aware, no amount of mass can cause anything like a rip in space-time.
 
  • #68
Chalnoth said:
Even more striking, however, is what happens inside the protons and neutrons. The masses of the individual quarks that make up the proton and neutron are only around 1-2% of the total mass. The rest of the mass comes from the binding energy of the quarks.

Intreresting...

Are you saying that whilst the quarks are bounded together inside the protons and neutrons that about 98% of that mass is in the form of binding energy?

It would seem to me that what happens is that this energy is released as a direct result of separating the quarks.

Whilst mass and energy can be interchanged - they are not equivalent states

One must be careful when comparing quarks on their own with quarks bounded together in a neutron or proton
 
  • #69
Driftwood1 said:
Intreresting...

Are you saying that whilst the quarks are bounded together inside the protons and neutrons that about 98% of that mass is in the form of binding energy?

It would seem to me that what happens is that this energy is released as a direct result of separating the quarks.
Nope, actually. The strong force doesn't allow that. If it did, protons would decay rather rapidly! The effect that prevents protons from breaking apart into their constituent states is known as "confinement", and it means that you have to put so much energy into a system to pull its quarks apart that soon quark/anti-quark pairs will pop into existence between the quarks you're pulling apart.

So in the case of, say, a proton, made of two ups and a down, if I started to pull on one of the quarks, eventually the tension would "snap", producing a quark/anti-quark pair. The new quark will bind with the proton, leaving it either as a proton or a neutron (depending upon whether the quark I leave behind is the same or different), and I'll be left holding onto the quark I was pulling on and an anti-quark in a bound state, which is known as a meson.

It turns out that the way the strong force behaves, protons are the lowest-mass configuration of three quarks, and you just can't pull them apart to make more energy. Other three-quark configurations all have more mass. This includes the neutron, which, if it is unbound, will decay into a proton, electron, and anti-neutrino after a little while. It's just that neutrons, when bound to protons, can be stable in some configurations.

Driftwood1 said:
Whilst mass and energy can be interchanged - they are not equivalent states
Nope, mass and energy are equivalent. Mass is non-kinetic energy. That is all.
 

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