Could you check if these two are equivalent?

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SUMMARY

The discussion centers on the equivalence of two conditions in the ratio test for series convergence. The first condition states that the series diverges if abs{a(n+1)/a(n)} > 1 for n≥N, where N is a fixed integer. The second condition proposes using lim inf abs{a(n+1)/a(n)} > 1 instead. Participants confirm that the two conditions are equivalent when the inequality is adjusted from ≥ to >, emphasizing that if the limit equals one, the ratio test is inconclusive.

PREREQUISITES
  • Understanding of series convergence tests, specifically the ratio test.
  • Familiarity with the concept of limits and lim inf in mathematical analysis.
  • Knowledge of absolute values in sequences and their implications.
  • Basic proficiency in mathematical notation and inequalities.
NEXT STEPS
  • Study the implications of the ratio test in series convergence.
  • Explore the concept of lim inf and its applications in analysis.
  • Review cases where the ratio test is inconclusive and alternative tests.
  • Investigate the properties of absolute values in sequences and series.
USEFUL FOR

Mathematics students, educators, and anyone studying series convergence and analysis techniques will benefit from this discussion.

Chsoviz0716
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Hi guys,

This is from so called ratio test, which says

The series Ʃa(n) diverges if abs{a(n+1)/a(n)} ≥ 1 for n≥N where N is some fixed integer.

I was wondering if I could replace the condition with lim inf abs{a(n+1)/a(n)} ≥ 1.

So basically what I'm asking is whether these two below are equivalent or not.
1. abs{a(n+1)/a(n)} ≥ 1 for n≥N where N is some fixed integer
2. lim inf abs{a(n+1)/a(n)} ≥ 1

*a(n) means nth term in the sequence, and abs means absolute value.

Thank you in advance.
 
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Chsoviz0716 said:
Hi guys,

This is from so called ratio test, which says

The series Ʃa(n) diverges if abs{a(n+1)/a(n)} ≥ 1 for n≥N where N is some fixed integer.
No, it doesn't say that. You need to replace "\ge" with ">".

I was wondering if I could replace the condition with lim inf abs{a(n+1)/a(n)} ≥ 1.

So basically what I'm asking is whether these two below are equivalent or not.
1. abs{a(n+1)/a(n)} ≥ 1 for n≥N where N is some fixed integer
2. lim inf abs{a(n+1)/a(n)} ≥ 1
Yes, if you replace that \ge with ">" in each.

*a(n) means nth term in the sequence, and abs means absolute value.

Thank you in advance.
 
If it equals one, the ratio test is inconclusive.
 

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